Calling show on a visible element modifies the display type to block, despite it being flex

I encountered some unwanted behavior when using show/hide to filter a list of elements specifying _display:flex_.

When calling the correct sequence everything works OK. So calling _hide_ first seems to register the original display type before setting _display:none_. Then after calling _show_, _display:flex_ is restored.

Calling _show_ on an element that is already visible causes the display type to change to _block_. And it never reverts to _flex_ in my case. This causes undesired changes to the layout. Ideally this method should have no effect in this case.

I've worked around this to make sure _show_ is never called on visible elements, but I think this should be default behavior.

PS. The docs state that show/hide switches between none and block. But this is obviously not the case since it also switches to flex.

Beginne damit, die show/hide-Implementierung zu lokalisieren und die gemeldete Sequenz mit einem Element zu reproduzieren, dessen display flex ist. Überprüfe, dass der Aufruf von show bei einem bereits sichtbaren Element dessen display-Typ unverändert lässt, während das bestehende hide-then-show-Verhalten weiterhin flex wiederherstellt.

Vom Indexierungsmodell aus dem Issue-Text verfasst.