arduino / arduino/ArduinoCore-API

shiftIn and shiftOut do not work with SPI_MODE 3 and 4

未关闭
#94 4 条评论 0 个 reaction 已指派 0 人 在 GitHub 查看
主要语言
C++
星标
306
派生
150
PR 合并指标
30 天内没有已合并 PR

描述

The solution described here might well fix several other problems in this thread where bits go missing or additional bits appear...
I was trying to use the standard Arduino shiftIn and shiftOut to operate a 74HC165 shift register. I found that it always clocked one too many bits, and therefore shifted all the bits to the left, losing the top one. This did not happen when I used hardware SPI (the SPI library).
I therefore took a close look at the source code for shiftIn and shiftOut in (wiring_shift.c) and soon spotted the problem: shiftIn and shiftOut assume a clock polarity of 0. _**They will therefore only work with SPI_MODE0 and 1.**_

This can be fixed by inverting the clock signal if the SPI_MODE is 3 or 4. I give my solution below. The functions require the SPI mode as an additional parameter, using the Arduino standard definitions SPI_MODE0 etc.
While I was at it, I gained a little speed by taking the test for MSBFIRST or LSBFIRST outside the bit loop and by declaring the method ‘inline’.
I have tested NEWshiftIn with the 74HC165 shift register (SPI_MODE3) and it works fine. I have not tested NEWshiftOut yet as I do not have a MOD3 or 4 device output to test it with. I have also not tested the timings to see if there is a real improvement, as I do not have access to the necessary equipment at the moment. I will be happy to hear from anyone who does any of these tests.
Happy shifting in SPI_MODES 3 and 4!
```cpp
// ===============================================================================================================================
// New version of shiftIn() and shiftOut with the clock polarity bug removed
// Requires SPI_MODE as a parameter
// Also speeded up by taking the bit direction test out of the loop
// Andrew W Symons 9-Aug-2018
//
// SHIFT IN
//
inline uint8_t NEWshiftIn(uint8_t dataPin, uint8_t clockPin, uint8_t bitOrder, uint8_t spiMode )
{
uint8_t value = 0;
uint8_t i;

uint8_t clock_polarity = spiMode >> 1 ;
switch ( bitOrder )
{
case LSBFIRST:
{
for (i = 0; i < 8; ++i)
{
digitalWrite(clockPin, HIGH ^ clock_polarity );
value |= digitalRead(dataPin) << i;
digitalWrite(clockPin, LOW ^ clock_polarity );
} ;
} ;
break ;

case MSBFIRST:
{
for (i = 0; i < 8; ++i)
{
digitalWrite(clockPin, HIGH ^ clock_polarity );
value |= digitalRead(dataPin) << (7 - i);
digitalWrite(clockPin, LOW ^ clock_polarity );
} ;
} ;
break ;
} ;
return value;
} ;
//
// ===============================================================================================================================
// SHIFT OUT
//
inline void NEWshiftOut(uint8_t dataPin, uint8_t clockPin, uint8_t bitOrder, uint8_t val, uint8_t spiMode )
{
uint8_t i;
uint8_t clock_polarity = spiMode >> 1 ;
switch ( bitOrder )
{
case LSBFIRST:
{
digitalWrite(dataPin, !!(val & (1 << i)));
digitalWrite(clockPin, HIGH ^ clock_polarity );
digitalWrite(clockPin, LOW ^ clock_polarity );
} ;
break ;

case MSBFIRST:
{
digitalWrite(dataPin, !!(val & (1 << (7 - i))));
digitalWrite(clockPin, HIGH ^ clock_polarity );
digitalWrite(clockPin, LOW ^ clock_polarity );
} ;
break ;
} ;
} ;
//
// ===============================================================================================================================
// END OF FILE
//
```

贡献指南

这个仓库没有索引到贡献指南

调研方向

从 wiring_shift.c 开始,将 shiftIn() 和 shiftOut() 与 SPI library 对 SPI 模式的处理进行比较。在受影响的时钟模式下重现报告的 74HC165 行为,然后验证对于现有模式和位顺序,标准移位行为仍然正确。当软件函数能够处理报告的模式且不遗漏或添加位时,即表示完成。

由索引模型根据 Issue 内容生成。

评估

技术栈
cpp
领域
embedded-iot
Issue 类型
缺陷
难度
4/5
预计耗时
3-5 天
活跃度
停滞
描述清晰度
基本清楚
新手友好度
42/100

把新 issue 发到你的邮箱

精选适合新手参与的 GitHub issue 摘要。