tint and shade function results are reverse of what they should be.

I have these 2 color functions:

```
@function tint($color, $percentage) { @return mix($color, #fff, $percentage); }
@function shade($color, $percentage) { @return mix($color, #000, $percentage); }
```

They take a color and mix it with white or black, respectively.
used as `$mycolor: tint(#0072b8, 10%);`

This should be a very light blue, 10% blue and 90% white. It looks right when used in the CSS/HTML.
But it shows as the reverse -- 90% blue, 10% white!

If I tried the reverse `$mycolor: tint(#0072b8, 90%);` it looks very light in your preview, but shows up the opposite in the css.

Look at the code that handles Sass/SCSS color functions, likely in a file parsing colors from stylesheets. The issue is that the tint and shade functions are displaying the mixed color incorrectly in the preview. Start by finding where these functions are evaluated or displayed, compare the expected mix ratio with the actual output, and adjust the calculation or display logic. Check the CSS output to confirm the fix matches the intended color.

索引モデルが issue の本文から書いたものです。