[Feature request] Support for the upvalue limit

還沒有人認領這個 Issue。

Functions in Lua 5.1 (and LuaJIT) can only reference up to 60 upvalues.

For example, the following code does not compile in Lua 5.1 ("lua5.1: upvals.lua:4: function at line 3 has more than 60 upvalues") but LuaLS accepts it without any warning when the version is set to 5.1. Ideally this would be handled directly in the parser similar to the 200 local limits.

```
local a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12, a13, a14, a15, a16, a17, a18, a19, a20, a21, a22, a23, a24, a25, a26, a27, a28, a29, a30, a31, a32, a33, a34, a35, a36, a37, a38, a39, a40, a41, a42, a43, a44, a45, a46, a47, a48, a49, a50, a51, a52, a53, a54, a55, a56, a57, a58, a59, a60, a61

function Foo()
print(a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12, a13, a14, a15, a16, a17, a18, a19, a20, a21, a22, a23, a24, a25, a26, a27, a28, a29, a30, a31, a32, a33, a34, a35, a36, a37, a38, a39, a40, a41, a42, a43, a44, a45, a46, a47, a48, a49, a50, a51, a52, a53, a54, a55, a56, a57, a58, a59, a60, a61)
end
```

從處理現有 200 個區域變數限制的 parser 開始，追蹤 Lua 5.1 和 LuaJIT 如何計算 upvalues。為超過 60 個 upvalues 的函式新增相應的限制警告，然後執行 parser 測試或根據範例新增一個案例，以驗證 Lua 5.1 回報該錯誤。

由索引模型根據 Issue 內容生成。