[Feature request] Support for the upvalue limit

Functions in Lua 5.1 (and LuaJIT) can only reference up to 60 upvalues.

For example, the following code does not compile in Lua 5.1 ("lua5.1: upvals.lua:4: function at line 3 has more than 60 upvalues") but LuaLS accepts it without any warning when the version is set to 5.1. Ideally this would be handled directly in the parser similar to the 200 local limits.

local a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12, a13, a14, a15, a16, a17, a18, a19, a20, a21, a22, a23, a24, a25, a26, a27, a28, a29, a30, a31, a32, a33, a34, a35, a36, a37, a38, a39, a40, a41, a42, a43, a44, a45, a46, a47, a48, a49, a50, a51, a52, a53, a54, a55, a56, a57, a58, a59, a60, a61

function Foo()
	print(a1, a2, a3, a4, a5, a6, a7, a8, a9, a10, a11, a12, a13, a14, a15, a16, a17, a18, a19, a20, a21, a22, a23, a24, a25, a26, a27, a28, a29, a30, a31, a32, a33, a34, a35, a36, a37, a38, a39, a40, a41, a42, a43, a44, a45, a46, a47, a48, a49, a50, a51, a52, a53, a54, a55, a56, a57, a58, a59, a60, a61)
end

从处理现有 200 个局部变量限制的 parser 开始，跟踪 Lua 5.1 和 LuaJIT 如何计算 upvalues。为超过 60 个 upvalues 的函数添加相应的限制警告，然后运行 parser 测试或根据示例添加一个用例，以验证 Lua 5.1 报告该错误。