Generates SyntaxError if a path parameter without a default value follows another that has a default value

使用报告中的最小 OpenAPI 规范重现该问题，并检查构建路径参数的生成 _get_kwargs 签名的生成器路径。通过成功生成客户端，并验证必需的路径参数可以位于具有默认值的参数之后且不会产生 Python SyntaxError，来确认修复有效。

Describe the bug
Fails to generate client when a path parameter without a default value follows another one that has a default value.

Message:

Error(s) encountered while generating, client was not created
ruff failed
SyntaxError: Parameter without a default cannot follow a parameter with a default

OpenAPI Spec File
Motivating api: https://avaandmed.keskkonnaportaal.ee/swagger/index.html ("File of document")
Minimum example:

openapi: 3.0.0
info:
  title: Minimal Repro for Parameter Order Bug
  version: 1.0.0
paths:
  /test/{has_default}/{no_default}:
    get:
      summary: Test endpoint with required path params, some with defaults
      parameters:
        - name: has_default
          in: path
          required: true
          schema:
            type: string
            default: default_value
          description: Required path param with default
        - name: no_default
          in: path
          required: true
          schema:
            type: integer
          description: Required path param, no default
      responses:
        '200':
          description: OK
          content:
            application/json:
              schema:
                type: object
                properties:
                  result:
                    type: string

Desktop (please complete the following information):

• OS: Ubuntu 22.04.5 LTS
• Python Version: 3.10.12
• openapi-python-client version 0.25.2

Additional context
The generated function signature for _get_kwargs looks like this:

def _get_kwargs(
    has_default: str = 'default_value',
    no_default: int,
) -> dict[str, Any]:

The issue does not occur for query parameters, as the generator emits keyword-only arguments (*) for them. It only occurs for path parameters, which are emitted as positional-or-keyword arguments.