full scan in utubettl take()
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Descrizione
The take() method in utubettl does a linear search for a task from an available utube.
In case there are many tasks in the same utube, calling take() will result in a full scan.
This can be improved by adding the 'utube' field to the status index, like this:
- parts = {i_status, str_type(), i_pri, num_type(), i_id, num_type()}
+ parts = {i_status, str_type(), i_pri, num_type(), i_utube, num_type(), i_id, num_type()}
And then using it in the take() method, quickly skipping taken utubes.
Code to demonstrate the full scan:
local queue = require('queue')
box.once('access:v1', function()
box.schema.user.grant('guest', 'read,write,execute', 'universe')
queue.create_tube('q1', 'utubettl', {})
for i=1,10^6 do
queue.tube.q1:put('task', {utube='u1'})
end
end)
local log = require 'log'
log.info('insert done, beginning test')
local fiber = require 'fiber'
local clock = require 'clock'
local start_time = clock.time()
local nworkers = 3
local chan = fiber.channel(nworkers)
for i = 1, nworkers do
fiber.create(function()
local myid = i
while true do
chan:put(1)
log.info('worker %d calls take...', myid)
local task = queue.tube.q1:take()
log.info('worker %d got task', myid)
queue.tube.q1:ack(task[1])
log.info('worker %d ack task', myid)
fiber.yield() -- give other workers a chance to work
end
end)
end
for i = 1, 2*nworkers do
chan:get()
end
log.info('test took %d seconds', clock.time() - start_time)
os.exit(0)
output (utubettl.lua was modified to log the number of iterations in take()):
2019-09-17 20:42:48.838 [12519] main/101/init.lua I> insert done, beginning test
2019-09-17 20:42:48.838 [12519] main/114/lua I> worker 1 calls take...
2019-09-17 20:42:48.838 [12519] main/115/lua I> worker 2 calls take...
2019-09-17 20:42:54.127 [12519] main/115/lua I> (999999 iterations in utubettl take())
2019-09-17 20:42:54.128 [12519] main/116/lua I> worker 3 calls take...
2019-09-17 20:42:59.855 [12519] main/116/lua I> (999999 iterations in utubettl take())
2019-09-17 20:42:59.855 [12519] main/114/lua txn.c:314 W> too long WAL write: 1 rows at LSN 1000022: 11.017 sec
2019-09-17 20:42:59.855 [12519] main/114/lua I> worker 1 got task
2019-09-17 20:42:59.855 [12519] main/114/lua I> worker 1 ack task
2019-09-17 20:42:59.855 [12519] main/114/lua I> worker 1 calls take...
2019-09-17 20:43:05.866 [12519] main/114/lua I> (999998 iterations in utubettl take())
2019-09-17 20:43:05.867 [12519] main/115/lua txn.c:314 W> too long WAL write: 1 rows at LSN 1000024: 6.012 sec
2019-09-17 20:43:05.867 [12519] main/115/lua I> worker 2 got task
2019-09-17 20:43:05.867 [12519] main/115/lua I> worker 2 ack task
2019-09-17 20:43:05.867 [12519] main/115/lua I> worker 2 calls take...
2019-09-17 20:43:11.836 [12519] main/115/lua I> (999997 iterations in utubettl take())
2019-09-17 20:43:11.836 [12519] main/114/lua txn.c:314 W> too long WAL write: 1 rows at LSN 1000026: 5.969 sec
2019-09-17 20:43:11.836 [12519] main/114/lua I> worker 1 got task
2019-09-17 20:43:11.836 [12519] main/114/lua I> worker 1 ack task
2019-09-17 20:43:11.837 [12519] main/114/lua I> worker 1 calls take...
2019-09-17 20:43:17.140 [12519] main/114/lua I> (999996 iterations in utubettl take())
2019-09-17 20:43:17.140 [12519] main/115/lua txn.c:314 W> too long WAL write: 1 rows at LSN 1000028: 5.304 sec
2019-09-17 20:43:17.140 [12519] main/115/lua I> worker 2 got task
2019-09-17 20:43:17.141 [12519] main/115/lua I> worker 2 ack task
2019-09-17 20:43:17.141 [12519] main/115/lua I> worker 2 calls take...
2019-09-17 20:43:22.495 [12519] main/115/lua I> (999995 iterations in utubettl take())
2019-09-17 20:43:22.495 [12519] main/114/lua txn.c:314 W> too long WAL write: 1 rows at LSN 1000030: 5.354 sec
2019-09-17 20:43:22.495 [12519] main/114/lua I> worker 1 got task
2019-09-17 20:43:22.495 [12519] main/114/lua I> worker 1 ack task
2019-09-17 20:43:22.495 [12519] main/114/lua I> worker 1 calls take...
2019-09-17 20:43:28.938 [12519] main/114/lua I> (999994 iterations in utubettl take())
2019-09-17 20:43:28.938 [12519] main/115/lua txn.c:314 W> too long WAL write: 1 rows at LSN 1000032: 6.443 sec
2019-09-17 20:43:28.938 [12519] main/115/lua I> worker 2 got task
2019-09-17 20:43:28.938 [12519] main/115/lua I> worker 2 ack task
2019-09-17 20:43:28.938 [12519] main/115/lua I> worker 2 calls take...
2019-09-17 20:43:34.251 [12519] main/115/lua I> (999993 iterations in utubettl take())
2019-09-17 20:43:34.251 [12519] main/101/init.lua I> test took 45 seconds
cpu usage is 100% during the whole test and it is hard for producers to put new tasks in the queue, because the lua thread is so busy.
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- Leggi tutta la issue e poi la guida ai contributi del progetto.
- Commenta sulla issue per dire che te ne occupi tu — evita che due persone facciano lo stesso lavoro.
- Fai un fork del repository e lavora su un branch.
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Direzione di ricerca
Inizia da utubettl.lua, esamina il metodo take() e la definizione dell’indice status mostrata nell’issue. Esegui la riproduzione fornita con un milione di task per osservare la scansione completa, quindi verifica che take() salti in modo efficiente le utubes già prese continuando a selezionare correttamente i task disponibili.
Scritto dal modello di indicizzazione a partire dal testo della issue.
Valutazione
- Stack tecnologico
- lua
- Ambito
- backend
- Tipo di issue
- Bug
- Difficoltà
- 3/5
- Tempo stimato
- 1-2 giorni
- Stato di attività
- Ferma
- Chiarezza
- Specificata chiaramente
- Idoneità per principianti
- 45/100