Inconsistent TypeScript behavior with optional arguments in useNavigation

When using the useNavigation hook from @react-navigation/native in TypeScript, optional arguments are not being correctly inferred and produce a type error.

Expected Behavior:

Optional arguments should be correctly inferred and not produce a type error.

Actual Behavior:

Optional arguments produce a type error, requiring the use of the // @ts-ignore comment to suppress the error.

Steps to Reproduce:

• Use the useNavigation hook with an optional argument.
• Attempt to pass a string value as the optional argument.
• Observe the type error.

import { useNavigation } from '@react-navigation/native';

const navigation = useNavigation();

const navigate = (screenName?: string) => {
  // Argument of type 'string' is not assignable to parameter of type 'never'
  navigation.navigate(screenName)
  // Workaround with // @ts-ignore
  // @ts-ignore
  navigation.navigate(screenName)
}

先重現 issue 中 useNavigation 範例的 TypeScript 錯誤，然後檢查 @react-navigation/native 中 useNavigation 的進入點及其型別定義。完成的標準是：可接受選用的 string 引數，而不需要使用 @ts-ignore 註解，同時維持正確的導覽型別。