Type fails to get "refined" on branch when `is None`-check happens in variable assignment

• Are you reporting a bug, or opening a feature request? Bug
• Please insert below the code you are checking with mypy:

from typing import Optional

def bar(var: str):
    pass

def foo(var: Optional[str]=None):
    var_not_None = not (var is None)
    if var_not_None:
        # var can only be a `str` at this point,
        # but `mypy` complains that
        # Argument 1 to "bar" has incompatible type "Optional[str]"; expected "str"
        bar(var)

def foo2(var: Optional[str]=None):
    if not(var is None):
        # no complaints from mypy
        bar(var)

• What is the actual behavior/output?

Running mypy on this reproducer returns:

error: Argument 1 to "bar" has incompatible type "Optional[str]"; expected "str" Found 1 error in 1 file (checked 1 source file)

• What is the behavior/output you expect?

No errors, both foo2 and foo are equivalent.

• What are the versions of mypy and Python you are using?

mypy 0.782 and Python 3.6.8

• Do you see the same issue after installing mypy from Git master?

Yup, unless I did something wrong 😅

Summary:

When you have an Optional[str]-typed variable var, one would expect that an not (var is None) check in an if-statement should tell mypy that all code within that branch has that the variable has type str. Indeed, mypy shows the expected behaviour for this, as shown in function foo2 above.

However, there are many instances where you want to check if a variable is None outside of the if-statement. For instance, if your if-statement were to check many boolean conditions at once. In this situation, one may save the result of the check into a variable. This is the case in the foo function above, where mypy complains.

I suspect this problem may not be solvable in the general case, but perhaps we can improve the status-quo nonetheless to catch this error.

If this is a beginner-friendly bug, I would love to help fix it! I've been meaning to get involved with the mypy project; just some guidance would do. Thanks!

Es wird keine Quelldatei oder kein Test genannt. Beginne damit, den bereitgestellten Python-Reproduzierer auszuführen, und vergleiche die Typenverengung in foo mit foo2; abgeschlossen ist die Aufgabe, wenn die auf Zuweisung basierende None-Prüfung keinen incompatible-type-Fehler erzeugt und das bestehende Verhalten beibehält.