Typo in kwarg to overloaded function results in message about type mismatch

Bug Report

Passing an incorrectly named kwarg to an overloaded function results in a misleading error message about types:

from typing import overload

@overload
def foo(bar: int) -> int:
    ...

@overload
def foo(bar: None) -> None:
    ...
    
def foo(bar: int | None) -> int | None:
    ...
    
foo(baz=42)  # typo: 'baz' should be 'bar'

error: No overload variant of "foo" matches argument type "int"  [call-overload]
note: Possible overload variants:
note:     def foo(bar: int) -> int
note:     def foo(bar: None) -> None

To Reproduce
https://mypy-play.net/?mypy=latest&python=3.10&gist=0c0b7a4699e67b65d38eb182fb75c444

Expected Behavior
A message such as error: Unexpected keyword argument "baz" for "foo" [call-arg] (which is what you get when the function is not overloaded).

Actual Behavior
error: No overload variant of "foo" matches argument type "int" [call-overload]

Your Environment

• Mypy version used: 1.0.0

Commencez par le reproducer mypy-play lié et suivez la vérification des appels à overload pour les arguments nommés. Ajoutez un test de régression pour l’argument mal orthographié baz, puis vérifiez que le diagnostic signale un argument nommé inattendu plutôt qu’une incompatibilité de types de overload.