Typo in kwarg to overloaded function results in message about type mismatch

Bug Report

Passing an incorrectly named kwarg to an overloaded function results in a misleading error message about types:

from typing import overload

@overload
def foo(bar: int) -> int:
    ...

@overload
def foo(bar: None) -> None:
    ...
    
def foo(bar: int | None) -> int | None:
    ...
    
foo(baz=42)  # typo: 'baz' should be 'bar'

error: No overload variant of "foo" matches argument type "int"  [call-overload]
note: Possible overload variants:
note:     def foo(bar: int) -> int
note:     def foo(bar: None) -> None

To Reproduce
https://mypy-play.net/?mypy=latest&python=3.10&gist=0c0b7a4699e67b65d38eb182fb75c444

Expected Behavior
A message such as error: Unexpected keyword argument "baz" for "foo" [call-arg] (which is what you get when the function is not overloaded).

Actual Behavior
error: No overload variant of "foo" matches argument type "int" [call-overload]

Your Environment

• Mypy version used: 1.0.0

Start with the linked mypy-play reproducer and trace overload call checking for keyword arguments. Add a regression test for the misspelled baz argument, then verify the diagnostic reports an unexpected keyword argument rather than an overload type mismatch.