_wave_parameters in wave.py should be public

Feature or enhancement

Make the named tuple _wave_parameters public. This nameed tuple defines the inputs to Wave_write.setparams which is a public method that users would want to call. To best create an input to setparams one would ideally first make a _wave_parameters named tuple.

This is especially true in a typed environment (see https://github.com/python/typeshed/issues/8322) but I feel it would be useful for all users of the wave module.

Pitch

Currently if one wants to call setparams in a typed setting, the only option is to use the private type:

import wave
with wave.open("test.wav", "wb") as wav_file:
    params = wave._wave_params(
        nchannels=1, sampwidth=2, framerate=16_000, nframes=0, comptype="NONE", compname="NONE",
    )
    wav_file.setparams(params)

There is no way to call setparams in a typed environment without using the wave._wave_params. If instead it was made public, all users could use the readable version of the parameters above, rather than pass in a tuple without kowing which numbers meant waht.

Previous discussion

see https://github.com/python/typeshed/issues/8322

Lisez Lib/wave.py autour du named tuple à la ligne 89 et du point d’entrée Wave_write.setparams. Résolvez les deux graphies du nom du tuple présentes dans l’issue, puis vérifiez que le nom public qui en résulte peut être construit par les utilisateurs et transmis à setparams sans modifier la signification de ses paramètres.