multiprocessing.Process generates FileNotFoundError when argument isn't explicitly referenced
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描述
Bug report
This is a continuation for the possible bug mentioned in issue https://github.com/python/cpython/issues/82236 which was closed because DonnyBrown, the submitter, didn't provide enough information.
DonnyBrown was getting a FileNotFoundError when starting a process with multiprocessing.Process that uses an argument that doesn't have an explicit reference. I'm able to reproduce the same error using the test code DonnyBrown provided in that issue on Ubuntu Desktop LTS 22.04 x86-64 with CPython 3.10.4. @iritkatriel mentioned that they were unable to reproduce the error on Windows 10 with Python 3.10.
I can also reproduce the error using this slightly modified/simpler version of DonnyBrown's test code that I have been testing:
import multiprocessing
def demo(argument):
print(argument)
if __name__=="__main__":
multiprocessing.set_start_method("spawn") # Changing this to "fork" (on platforms where it is
# available) can also cause the below code to work.
process=multiprocessing.Process(target=demo, args=[multiprocessing.Value("i", 0)]) # FAILS
#process=multiprocessing.Process(target=demo, args=[0]) # WORKS
#reference_To_Number=multiprocessing.Value("i", 0) # WORKS
#process=multiprocessing.Process(target=demo, args=[reference_To_Number])
process.start()
process.join()
The traceback I get with the above code is:
Traceback (most recent call last):
File "<string>", line 1, in <module>
File "/usr/lib/python3.10/multiprocessing/spawn.py", line 116, in spawn_main
exitcode = _main(fd, parent_sentinel)
File "/usr/lib/python3.10/multiprocessing/spawn.py", line 126, in _main
self = reduction.pickle.load(from_parent)
File "/usr/lib/python3.10/multiprocessing/synchronize.py", line 110, in __setstate__
self._semlock = _multiprocessing.SemLock._rebuild(*state)
FileNotFoundError: [Errno 2] No such file or directory
The above code can be made to work on my test system by making any of the following changes:
- Change the process start method to "fork" instead.
- Change the process argument to a simple integer instead of a multiprocessing.Value.
- Assign the multiprocessing.Value to a variable and change the process argument to use the variable.
I'm not a Python expert so maybe this is the expected behavior when spawning a process directly with a multiprocessing.Value but it does seem odd that making any of the above mentioned changes causes the code to work or that (based on @iritkatriel's success with DonnyBrown's test code) running it on Windows 10 (which uses the "spawn" start method) will probably cause the code to work.
Your environment
- CPython versions tested on: 3.10.4
- Operating system and architecture: Linux, Ubuntu Desktop LTS 22.04, x86-64
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研究方向
在 Linux 上使用 spawn 啟動方法重現所提供的腳本,然後閱讀 traceback 附近的 multiprocessing/spawn.py 和 multiprocessing/synchronize.py。比較 inline 的 multiprocessing.Value 引數與明確參照的值以及 fork 行為。完成的標準是:已解決或明確記錄所回報的 FileNotFoundError,並為 reproducer 提供回歸涵蓋。
由索引模型根據 Issue 內容生成。
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