Improve syntax error for nonlocal not in a nested function

Using nonlocal inside a non-nested function to refer to a global gives the syntax error "no binding for nonlocal 'name' found" even if the global 'name' exists. This is confusing. Improve the error message by making it clear that the problem is not that variable 'name' doesn't exist, but that the function is not nested inside another function containing a variable 'name'.

Suggestion: if nonlocal is used in a non-nested function where there is no surrounding function (e.g. either a global level function or one defined inside a class), rather than reporting that there is no binding found, make the error message more specific:

"nonlocal can only be used in function nested inside another function; perhaps try global instead?"

As evidence that this error message is not clear, see #92983 where the submitter @snoopyjc was mislead into thinking that the problem was the loop variable rather than the lack of nested function.

首先定位編譯器處理 nonlocal 錯誤的程式碼，以及針對無效巢狀函式作用域的回歸測試。驗證非巢狀函式的現有訊息，然後讓最終行為回報缺少外圍函式，並改為建議使用 global。