PyMutex re-entrancy not documented, confusing existing doc

Documentation

The doc for PyMutex is very unclear if the mutex is re-entrant. Can PyMutex_Lock be called multiple times in the same thread? Do there have to be an equal number of PyMutex_Unlock calls?

The PyMutex_Lock doc says it will succeed if the thread already has the lock. PyMutex_Unlock makes no mention of it having to be called in the same thread, or if any thread is okay.

Elsewhere it says the mutex is one byte, which is not enough to do any form of counting.

The relevance is that I have C code wrapping a library and that library can make callbacks. That means there are multiple paths through the call stack. A re-entrant counting mutex would work perfectly, and it is impossible to use a non-counted lock in that scenario, short of implementing another layer of locking to do the counting.

Linked PRs

• gh-146543

从 C 同步文档中的 PyMutex API 参考开始，并查看链接的 PR gh-146543。确定重复调用 PyMutex_Lock 时文档所规定的行为，以及 PyMutex_Unlock 所需的线程和调用次数，然后更新文档，明确说明这些规则。