python / python/cpython

`zipfile`: file type issues

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stdlib type-bug
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Python
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Descrizione

Bug report

Bug description:

Hey.

I think there exist a number of issues (which may, depending on how code is used, in principle even be security relevant).

First, AFAIU, ZIP files may contain (at least) regular files, directories (as "standalone" items in the archive, like an empty directory) and symbolic links.

For example using the zip program:

$ mkdir empty
$ zip d.zip empty
  adding: empty/ (stored 0%)
$ ln -s /dev/null bar
$ zip --symlinks  s.zip bar 
  adding: bar (stored 0%)
$

When I open the one with the symlink in Python:

>>> import zipfile

>>> z = zipfile.ZipFile("s.zip", "r")
>>> z.namelist()
['bar']

>>> f = z.open("bar", "r")
>>> f.read()
b'/dev/null'

>>> i = z.getinfo("bar")
>>> i.is_dir()
False

>>> p = zipfile.Path(z, "bar")

>>> p.filename
PosixPath('s.zip/bar')

>>> p.is_dir()
False

>>> p.is_file()
True

>>> p.is_symlink()
True

>>>
  1. It's IMO debatable whether z.open("<symlink>", "r") should succeed or not. IMO zipfile.ZipFile.open() quite clearly is ZIP's open(), but that AFAIK, never opens symlinks but only follows them.
  2. Even if that behaviour is desired (i.e. like a os.readlink() for ZIPs), then it's still completely unexpected and the ZipFile object has no is_symlink()-method ... (only zipfile.Path has such, so one needs to create that first, which seems quite unhandy).
  3. Speaking of which zipfile.Path’s is_dir(), is_file() and is_symlink() functions seem either buggy or semantically inconsistent and/or badly documented.
    Usually, "file" means either any type of file (directory, symlink, device, etc.) or regular files (and sometimes also symlinks if they point to regular files).
    Here, the symlink points to nothing, so it cannot be the latter case. Also - see below - a directory wouldn't return True for is_file(), so the it's not the former either.
    The docs also don't meantion what "file" means.

Now the same with d.zip:

>>> import zipfile
>>> z = zipfile.ZipFile("d.zip", "r")
>>> z.namelist()
['empty/']

>>> f = z.open("empty/", "r")
>>> f.read()
b''

>>> i = archive_file.getinfo("empty/")
>>> i.is_dir()
True

>>> p = zipfile.Path(z,"empty/")
>>> p.filename
PosixPath('d.zip/empty')

>>> p.is_dir()
True

>>> p.is_file()
False

>>> p.is_symlink()
False

>>>
  1. IMO, that zipfile.ZipFile.open() succeeds on a directory (and gives an empty bytes) seems pretty strange at best. It does so even if the directory isn't empty but contains files.
  2. There's also that thing that sometimes that directory pathnames are suffixed by / and sometimes not. Maybe I've missed it but that doesn't seem to be documented, but may be crucial when e.g. matching filenames - and is IMO unexpected.
  3. As mentioned above, is_file() here is False, which would imply that the meaning of that function should be that a file is either a regular file or a regular file or a symbolic link pointing to such.

Cheers,
Chris.

CPython versions tested on:

3.13

Operating systems tested on:

Linux

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Direzione di ricerca

Inizia riproducendo gli esempi di Python 3.13 con zipfile.ZipFile.open(), ZipInfo.is_dir() e zipfile.Path.is_dir(), is_file() e is_symlink(). Leggi la documentazione e i test correlati di zipfile, quindi stabilisci la semantica prevista per directory, file regolari, collegamenti simbolici e barre finali prima di definire i criteri di completamento.

Scritto dal modello di indicizzazione a partire dal testo della issue.

Valutazione

Stack tecnologico
python
Ambito
operating-systems
Tipo di issue
Bug
Difficoltà
5/5
Tempo stimato
Più di una settimana
Stato di attività
Ferma
Chiarezza
Da chiarire
Idoneità per principianti
25/100

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