python / python/cpython

nogil `__len__` and `__eq__` break atomicity on sets and dicts

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#129,519 2 comentarios 0 reacciones 0 asignados Ver en GitHub

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interpreter-core topic-free-threading type-bug
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Python
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Descripción

Bug report

Bug description:

Hi,

We're a research group focused on testing concurrent runtimes. Our work-in-progress prototype found a violation of atomicity on the current nogil build when using set __len__ or __eq__ with other concurrent operations on the same set/dict. The program below shows the wrong behavior for __len__ and __ixor__:

import threading
import sys
def t0(b1,s,res):
    b1.wait()
    res.append(s.__len__())

def t1(b1,s,res):
    b1.wait()
    s.__ixor__({0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 'a'})

def Test():
  s =  {17, 'a', 'b', 18, 'c', 'd', 'e'}
  threads=[]
  barrier = threading.Barrier(2)
  res = []
  threads.append(threading.Thread(target= t0, args=(barrier, s,res)))
  threads.append(threading.Thread(target= t1, args=(barrier, s,res)))
  for i in range(0, len(threads)):
      threads[i].start()
  for i in range(0, len(threads)):
      threads[i].join()
  if res[0] not in { 7 , 32 }:
      print("found bug: " + str(res[0]))

print("test begin...")
for i in range(0,50000):
  threads = []
  if i % 1000 == 0:
      print(i)
  for i in range(0,100):
      threads.append(threading.Thread(target= Test))
  for t in threads:
      t.start()
  for t in threads:
      t.join()
print("test Done")

Operation __len__ should see the initial set and return 7 or the set after the __ixor__ completes and return 32. However, it can see internal changes made by __ixor__ and return different numbers. Here's an example execution:

test begin...
0
found bug: 9
found bug: 17
found bug: 22
found bug: 30
found bug: 9
found bug: 9
found bug: 9
found bug: 9
found bug: 9

We have observed the same problem when __len__ runs concurrently with other operations: symmetric_difference_update, __isub__, and update. We'll share these test below in a comment.

We observed the same problem when dict's __len__ runs concurrently with __ior__:

import threading
import sys
def t0(b1,s,res):
    b1.wait()
    res.append(s.__len__())
​
def t1(b1,s,res):
    b1.wait()
    s.__ior__({0: 0, 1: 1, 2: 2, 3: 3, 4: 4})
​
def Test():
  d =  {'k1': 'v1', 'k2': 'v2', 'k3': 3, 10: 10}
  threads=[]
  barrier = threading.Barrier(2)
  res = []
  threads.append(threading.Thread(target= t0, args=(barrier, d,res)))
  threads.append(threading.Thread(target= t1, args=(barrier, d,res)))
  for i in range(0, len(threads)):
      threads[i].start()
  for i in range(0, len(threads)):
      threads[i].join()
  if res[0] not in { 4, 9 }:
      print("found bug: " + str(res[0]))
​
print("test begin...")
for i in range(0,50000):
  threads = []
  if i % 1000 == 0:
      print(i)
  for i in range(0,100):
      threads.append(threading.Thread(target= Test))
  for t in threads:
      t.start()
  for t in threads:
      t.join()
print("test Done")

Again, the length of the dict should be either 4 or 9, depending on whether __ior__ took place. However, __len__ can see internal changes from __ior__ as shown by the output:

test begin...
0
found bug: 5
found bug: 6
found bug: 5
found bug: 5
found bug: 8
found bug: 7

Finally, we observed set's __eq__ to be able to access intermediate results of __isub__, as shown by the program below:

import threading
import sys
def t0(b1,s,res):
    b1.wait()
    s.__isub__({1, 'b', 'd', 17})

def t1(b1,s,res):
    b1.wait()
    res.append(s.__eq__({'a', 'b', 18, 'c', 'd', 'e'}))

def Test():
  s =  {'a', 17, 'b', 18, 'c', 'd', 'e'}
  threads=[]
  barrier = threading.Barrier(2)
  res = []
  threads.append(threading.Thread(target= t0, args=(barrier, s,res)))
  threads.append(threading.Thread(target= t1, args=(barrier, s,res)))
  for i in range(0, len(threads)):
      threads[i].start()
  for i in range(0, len(threads)):
      threads[i].join()
  if res[0] != False:
      print("found bug: " + str(res[0]))

print("test begin...")
for i in range(0,50000):
  threads = []
  if i % 1000 == 0:
      print(i)
  for i in range(0,100):
      threads.append(threading.Thread(target= Test))
  for t in threads:
      t.start()
  for t in threads:
      t.join()
print("test Done")

The original and resulting sets are never equal to the argument passed to __eq__, however the operation can see internal changes from __isub__ as shown by the ouput:

test begin...
0
found bug: True
found bug: True
found bug: True
found bug: True
found bug: True
found bug: True

@flypoodles and @overlorde are part of the team, adding them so they get notified about further discussion.

We note that we observed these outputs in several x86_64 machines and one ARM machine.

CPython versions tested on:

CPython main branch, 3.14

Operating systems tested on:

Linux

Guía de contribución

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Primeros pasos

  1. Lee el issue completo y luego la guía de contribución del proyecto.
  2. Comenta en el issue que vas a ocuparte — evita que dos personas hagan lo mismo.
  3. Haz un fork del repositorio y trabaja en una rama.
  4. Abre un pull request que haga referencia al número del issue.

Línea de trabajo

Comienza ejecutando los reproductores de Python en la rama principal de CPython y confirma los resultados intermedios de las operaciones de set y dict. Investiga las rutas de implementación de set/dict len, eq, ixor, ior y las actualizaciones relacionadas, usando los casos concurrentes reportados como pruebas de regresión. Se considera terminado cuando las operaciones concurrentes observan únicamente resultados válidos de antes o después, nunca un estado intermedio.

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python
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Tipo de issue
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