create_unix_server() removes listening unix socket, potentially from other process

Bug report

Bug description:

I made a mistake leading to reusing the same unix socket path for multiple Python processes, then as a surprise realized only the last process's unix socket listening, and none will be listening if the last process stopped.

I then realized this was implemented in https://github.com/python/asyncio/pull/441 for https://bugs.python.org/issue28399 which isn't clear on why deleting the original unix socket make sense. Assumingly it is for removing old unix socket files that's not in use, but apparently it can be removing listening sockets as well.

I don't think this should be intended behavior but open to any comment. Thanks.

To reproduce, with repro.py as below:

import os
import asyncio


class IdentityProtocol(asyncio.Protocol):
    """a protocol that politely replies server's pid then close connection"""

    def connection_made(self, transport):
        print('got new connection')
        transport.write(b'hello from pid=%d\r\n' % os.getpid())
        transport.close()


async def main():
    server = await asyncio.get_running_loop().create_unix_server(
            lambda: IdentityProtocol(), 'duplicatedpath.sock'
        )
    async with server:
        await server.serve_forever()


asyncio.run(main())

run two of such instances in separate terminals for the same working directory, and after each process created, use nc -CU duplicatedpath.sock which should simply show the pid of the last python process and exit.

CPython versions tested on:

3.10

Operating systems tested on:

Linux

Comece reproduzindo o comportamento com o repro.py fornecido e os comandos nc no Linux; em seguida, rastreie asyncio.create_unix_server() e revise o PR 441 e a issue 28399 vinculados. O trabalho estará concluído quando o comportamento de limpeza do socket não remover mais o socket Unix em escuta de outro processo e o cenário relatado estiver coberto por um teste de regressão.