Associativity of matmul unclear from grammar for m_expr

Documentation

6.7. Binary arithmetic operations shows the grammar rule

m_expr ::=  u_expr | m_expr "*" u_expr | m_expr "@" m_expr |
            m_expr "//" u_expr | m_expr "/" u_expr |
            m_expr "%" u_expr

in which all operators except @ for matmul are left-associative (meaning, a*b*c parses as m_expr a*b and u_expr c ) while @ is ambiguous: Does a@b@c parse as m_expr a@b and m_expr c or as m_expr a and m_expr b@c?

According to PEP 465, @ should have the same associativity as *. Should this grammar rule should reflect that by saying m_expr "@" u_expr, that is, with the right-hand side changed from m_expr to u_expr?

Linked PRs

• gh-138847
• gh-145636
• gh-149281

从 issue 中链接的“6.7 Binary arithmetic operations”部分开始，将其 m_expr 语法与 PEP 465 中规定的结合性进行比较。查看链接的 PR gh-138847、gh-145636 和 gh-149281；完成的标准是文档明确说明 @ 的结合性，并与规范一致。