Confusing example for PVector copy() method

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Section

Examples

Location of the error

https://processing.org/reference/PVector_copy_.html

Describe the error

In the documentation for the copy() method of the PVector class, the following code example is given:

PVector v1, v2;

void setup() {
  size(100, 100);
  v1 = new PVector(20.0, 30.0, 40.0);
  v2 = new PVector();
  v2 = v1.copy();
  ...

While not a factual error, it seems curious to me that v2 would be instantiated as a new PVector only to be assigned the result of v1.copy(). If .copy() creates a returns a new PVector object, then the initial assignment would have no effect. This led to some confusion amongst my students who had various incorrect assumptions about how .copy() works given the example code.

Suggested correction

PVector v1, v2;

void setup() {
  size(100, 100);
  v1 = new PVector(20.0, 30.0, 40.0);
  v2 = v1.copy();
  ...

Language

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Screenshots or references

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Additional context

No response

Commencez par la page de référence de PVector copy() liée dans l’issue et repérez sa section Examples. Vérifiez l’initialisation de l’objet et l’affectation de copie dans l’exemple, puis mettez à jour l’exemple afin qu’il n’effectue plus l’initialisation redondante. Vérifiez l’exemple de documentation rendu après la modification.