Unstable result while executing query

## Bug Report

Please answer these questions before submitting your issue. Thanks!

### 1. Minimal reproduce step (Required)
```sql
CREATE TABLE t0(c0 CHAR , c1 BLOB(173) , c2 CHAR );

UPDATE t0 SET c0='K', c2=-493926160;
ALTER TABLE t0 DROP c1;
CREATE ALGORITHM=UNDEFINED VIEW v0(c0) AS SELECT t0.c2 FROM t0 WHERE t0.c0;
REPLACE INTO t0 VALUES (NULL, '0'), ('0', 'X'), ('A', '0');
ADMIN CHECKSUM TABLE t0;
INSERT INTO t0(c0) VALUES ('6');

ALTER TABLE t0 ADD PRIMARY KEY(c2);
REPLACE INTO t0 VALUES ('g', '1');

INSERT IGNORE INTO t0 VALUES ('_', '(');
REPLACE INTO t0(c2) VALUES ('p');
UPDATE t0 SET c2=t0.c2, c0=((818354575)AND(-498102208)) WHERE 0.31994056953914873;
REPLACE INTO t0(c0, c2) VALUES ('A', '8');
ALTER TABLE t0 DISABLE KEYS;
REPLACE INTO t0(c0) VALUES ('-'), ('遞');
REPLACE INTO t0(c2, c0) VALUES (NULL, '-');

SELECT t0.c0 FROM t0 NATURAL RIGHT JOIN v0 GROUP BY ((v0.c0) IS NOT NULL) HAVING '0' UNION ALL SELECT t0.c0 FROM t0 NATURAL RIGHT JOIN v0 GROUP BY ((v0.c0) IS NOT NULL) HAVING (NOT ('0')) UNION ALL SELECT t0.c0 FROM t0 NATURAL RIGHT JOIN v0 GROUP BY ((v0.c0) IS NOT NULL) HAVING (('0') IS NULL);

```

### 2. What did you expect to see? (Required)
Executing last query will always return same result

### 3. What did you see instead (Required)
Executing last query multiple times will return different results

### 4. What is your TiDB version? (Required)
8.0.11-TiDB-v9.0.0-beta.1.pre-640-g24903d6b24

Beginne damit, die bereitgestellte SQL-Reproduktion auf TiDB 8.0.11-TiDB-v9.0.0-beta.1.pre-640-g24903d6b24 auszuführen, und führe das abschließende SELECT wiederholt aus. Konzentriere dich auf die Klauseln NATURAL RIGHT JOIN, GROUP BY, HAVING und UNION ALL; fertig ist die Aufgabe, wenn die abschließende Abfrage bei jeder Ausführung dasselbe Ergebnis liefert.

Vom Indexierungsmodell aus dem Issue-Text verfasst.