phpmyadmin / phpmyadmin/sql-parser

Views with CTEs parsed incorrectly

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bug
Langage dominant
PHP
Étoiles
485
Forks
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Description

Hi, parser has been working great for the most part but I ran into an issue today where I have multiple views with CTEs that get mixed together by the parser. I found that if I put parentheses around each view body definition the issue goes away, but MySQL does not require this.

Here is a minimal test script that demonstrates the issue:
test.php

Output from the test script on my machine follows. I am using phpmyadmin/sql-parser version 5.11.1 installed via composer.

-- SQL A:
CREATE VIEW view1 AS
WITH foo AS (SELECT abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz;

CREATE VIEW view2 AS
WITH foo AS (SELECT id, abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz;

-- Result A:
-- create VIEW view1
CREATE VIEW view1  AS WITH foo AS (SELECT abc FROM foo_table), bar AS (SELECT id, xyz FROM bar_table) SELECT foo.id AS `id`, foo.abc AS `abc`, bar.xyz AS `xyz` FROM foo LEFT JOIN bar USING (id) ORDER BY foo.abc ASC, bar.xyz ASCCREATE VIEW view2  AS WITH foo AS (SELECT id, abc FROM foo_table), bar AS (SELECT id, xyz FROM bar_table) SELECT foo.id AS `id`, foo.abc AS `abc`, bar.xyz AS `xyz` FROM foo LEFT JOIN bar USING (id) ORDER BY foo.abc ASC, bar.xyz ASC


-- SQL B:
CREATE VIEW view1 AS (
WITH foo AS (SELECT abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz);

CREATE VIEW view2 AS (
WITH foo AS (SELECT id, abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz);

-- Result B:
-- create VIEW view1
CREATE VIEW view1  AS  (
WITH foo AS (SELECT abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz)
-- create VIEW view2
CREATE VIEW view2  AS  (
WITH foo AS (SELECT id, abc FROM foo_table),
bar AS (SELECT id, xyz FROM bar_table)
SELECT foo.id AS id, foo.abc AS abc, bar.xyz AS xyz
FROM foo LEFT JOIN bar USING (id)
ORDER BY foo.abc, bar.xyz)

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Piste de recherche

Commencez par le script test.php lié et reproduisez la sortie à l’aide de phpmyadmin/sql-parser 5.11.1. Suivez la manière dont plusieurs instructions CREATE VIEW contenant des CTEs sont analysées, puis ajoutez une couverture pour la forme sans parenthèses et vérifiez que chaque vue reste distincte et correcte sans nécessiter de parenthèses.

Rédigé par le modèle d'indexation à partir du texte de l'issue.

Évaluation

Stack technique
mysql, php, sql
Domaine
databases
Type d'issue
Bug
Difficulté
4/5
Temps estimé
3-5 jours
Activité
Calme
Clarté
Plutôt claire
Accessibilité débutants
48/100

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