phpmyadmin / phpmyadmin/sql-parser
Incorrect type in SelectStatement::$expr when query has CASE-clause in selected fields
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- PHP
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描述
The public field SelectStatement::$expr is defined in a PHP docblock as an Expression[]. When parsing a query with a CASE statement, a CaseExpression object is present in this list, despite CaseExpression not extending Expression. This causes issues when explicitly requiring the Expression type as should be returned by SelectStatement::$expr.
Reproduction case
<?php
declare(strict_types=1);
use PhpMyAdmin\SqlParser\Components\Expression;
use PhpMyAdmin\SqlParser\Parser;
use PhpMyAdmin\SqlParser\Statements\SelectStatement;
include_once 'vendor/autoload.php';
$p = new Parser('SELECT a, CASE WHEN b IS NOT NULL THEN 1 ELSE 0 END as c FROM t');
$stmt = $p->statements[0];
if (! $stmt instanceof SelectStatement) {
throw new Exception('Could not parse select statement');
}
function acceptExpression(Expression $e): void {}
$expressions = $stmt->expr;
foreach ($expressions as $expression) {
acceptExpression($expression);
}
Expected behavior
I would expect this script to not error out as the $stmt->expr returns Expression[] according to its PHP docblock. Each element should therefore be compatible with Expression in my acceptExpression function.
Real behavior
$ php test.php
PHP Fatal error: Uncaught TypeError: acceptExpression(): Argument #1 ($e) must be of type PhpMyAdmin\SqlParser\Components\Expression, PhpMyAdmin\SqlParser\Components\CaseExpression given, called in /path/to/test.php on line 22 and defined in /path/to/test.php:18
Stack trace:
#0 /path/to/test.php(22): acceptExpression()
#1 {main}
thrown in /path/to/test.php on line 18
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调研方向
从 issue 中的 Parser 复现开始,检查选择 CASE 子句时 SelectStatement::$expr 是如何填充的。比较 Expression 和 CaseExpression 类型,并通过重新运行所提供的脚本来验证预期的契约;完成的标准是报告的 TypeError 不再发生,同时表达式列表仍保持正确的类型。
由索引模型根据 Issue 内容生成。
评估
- 技术栈
- php
- 领域
- databases
- Issue 类型
- 缺陷
- 难度
- 3/5
- 预计耗时
- 1-2 天
- 活跃度
- 停滞
- 描述清晰度
- 基本清楚
- 新手友好度
- 35/100