Support TypeScript executable without extension when flag is set

What is the problem this feature will solve?

When I write an executable utility like build-game, I have to expose the implementation detail of the language it's written in, like build-game.ts.

#!/usr/bin/env node
// This file is named `build-game` not `build-game.ts`. Only plain JavaScript is allowed.

const foo: number = 1 // Error: TypeScript encountered.
console.log(foo)

/home/user/bin/build-game:3
const foo: number = 1
      ^^^

SyntaxError: Missing initializer in const declaration
    at wrapSafe (node:internal/modules/cjs/loader:1624:18)
    at Module._compile (node:internal/modules/cjs/loader:1666:20)
    at Object..js (node:internal/modules/cjs/loader:1824:10)
    at Module.load (node:internal/modules/cjs/loader:1427:32)
    at Module._load (node:internal/modules/cjs/loader:1250:12)
    at TracingChannel.traceSync (node:diagnostics_channel:322:14)
    at wrapModuleLoad (node:internal/modules/cjs/loader:235:24)
    at Module.executeUserEntryPoint [as runMain] (node:internal/modules/run_main:152:5)
    at node:internal/main/run_main_module:33:47

Node.js v24.4.1

What is the feature you are proposing to solve the problem?

When --experimental-strip-types is set (or add a new flag), force TypeScript evaluation. This will allow a script to encapsulate all interpreter detail.

#!/usr/bin/env -S node --experimental-strip-types
// This file is named `build-game` not `build-game.ts`. TypeScript is allowed
// because the `--experimental-strip-types` flag was passed.

const foo: number = 1
console.log(foo)

What alternatives have you considered?

If the executable is in an NPM package, I can just alias it in the package.json. If the executable is in my ~/bin, I can just shell alias it. However, these are both limited and really prevent me from sharing scripts with nice names that work everywhere.

该 issue 没有指出任何实现文件、入口点或测试，因此请先定位 Node 的命令行标志处理和 TypeScript 的执行行为。验证在使用 --experimental-strip-types 时无扩展名可执行文件的预期行为，并确认现有的基于扩展名的行为保持不变。