microsoft / microsoft/TypeScript
Type instantiation for type level generic function
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Descrizione
🔍 Search Terms
type instantiation
type level generic function
generic return type
Related: https://github.com/microsoft/TypeScript/issues/40542, https://github.com/microsoft/TypeScript/issues/61133 and maybe https://github.com/microsoft/TypeScript/issues/52035?
Edit: Just found https://github.com/microsoft/TypeScript/issues/55435 and https://github.com/microsoft/TypeScript/issues/40179
✅ Viability Checklist
- This wouldn't be a breaking change in existing TypeScript/JavaScript code
- This wouldn't change the runtime behavior of existing JavaScript code
- This could be implemented without emitting different JS based on the types of the expressions
- This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, new syntax sugar for JS, etc.)
- This isn't a request to add a new utility type: https://github.com/microsoft/TypeScript/wiki/No-New-Utility-Types
- This feature would agree with the rest of our Design Goals: https://github.com/Microsoft/TypeScript/wiki/TypeScript-Design-Goals
⭐ Suggestion
#47607 added support for instantiation expressions, but those do not apply at the type level. I understand it'd be ambiguous in some cases (https://github.com/microsoft/TypeScript/pull/47607#issuecomment-1058192563), but in some cases there really isn't a reasonable workaround.
📃 Motivating Example
I actually have a very similar case to the example provided in https://github.com/microsoft/TypeScript/issues/40542
const provideBox = () => {
const box = <T>(value: T) => ({value});
return box;
};
type BoxMaker = ReturnType<typeof provideBox>
// type BoxMaker = <T>(value: T) => { value: T; }
type Box1<T> = ReturnType<BoxMaker<T>>;
// Type 'BoxMaker' is not generic.(2315)
const box = undefined as unknown as BoxMaker;
type Box2<T> = ReturnType<typeof box<T>>;
//type Box2<T> = { value: T; }
Compiler Options
{
"compilerOptions": {
"strict": true,
"noImplicitAny": true,
"strictNullChecks": true,
"strictFunctionTypes": true,
"strictPropertyInitialization": true,
"strictBindCallApply": true,
"noImplicitThis": true,
"noImplicitReturns": true,
"alwaysStrict": true,
"esModuleInterop": true,
"declaration": true,
"target": "ES2017",
"module": "ESNext",
"moduleResolution": "node"
}
}
Playground Link: Provided
💻 Use Cases
- What do you want to use this for?
In our case we have a more complex provideBox that accept arguments. We also need to rely on type inference for the generic type of the box function and its return value;
- What shortcomings exist with current approaches?
I cannot extract and export a generic type for a return value of a generic function if I don't have direct reference to the function.
- What workarounds are you using in the meantime?
The only workaround I found is to use a dummy runtime value to apply the type, and use and instantiation expression on that dummy value (see Box2 above)
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Direzione di ricerca
Inizia riproducendo l’esempio motivante nel link Playground fornito, quindi leggi le issue correlate e PR #47607 per comprendere il comportamento esistente delle espressioni di istanziazione e le ambiguità segnalate. Il lavoro è completato quando una forma a livello di tipo può estrarre il tipo restituito generico senza un valore runtime fittizio, producendo il risultato Box2 previsto e preservando il comportamento esistente.
Scritto dal modello di indicizzazione a partire dal testo della issue.
Valutazione
- Stack tecnologico
- typescript
- Ambito
- compilers
- Tipo di issue
- Funzionalità
- Difficoltà
- 5/5
- Tempo stimato
- Più di una settimana
- Stato di attività
- Ferma
- Chiarezza
- Abbastanza chiara
- Idoneità per principianti
- 35/100