Property is not assignable to the same property in generic base type

### 🔎 Search Terms

Property is not assignable to the same property in generic base type

### 🕗 Version & Regression Information

-This is the behavior in every version I tried, and I reviewed

### ⏯ Playground Link

https://www.typescriptlang.org/zh/play/?ts=5.8.3#code/IYIwzgLgTsDGEAJYBthjAgSgCwPYIG8AoBBUSGeBABwEsATAc1oDswAeAMQH0BRBAKYAPCAJb0MLAK4BbEAKgAaBDwBSAPgAUIKFLABHKQMgAuFd1UIAPud4BKM2uu2A3EQC+RFGgwAhZFIAZoEKgiJiElh4hCQ0DMxsXHxhouKSsvJK5hraugZGptnOPPaOFsXJscSkpFACEFJQLKQ6eobGEG6knp5AA

### 💻 Code

```ts
abstract class Rho {
abstract pidgins(brusquest: F_J | F_E): F_J | F_E;
}
class Bluffer extends Rho {
pidgins(brusquest: F_J | F_E): F_J | F_E
{
return brusquest;
}
}

```

### 🙁 Actual behavior

Property 'pidgins' in type 'Bluffer' is not assignable to the same property in base type 'Rho'.
Type '(brusquest: F_E | F_J) => F_E | F_J' is not assignable to type '(brusquest: F_E | F_J) => F_E | F_J'. Two different types with this name exist, but they are unrelated.
Type 'number | F_E | F_J' is not assignable to type 'F_E | F_J'.
Type 'number' is not assignable to type 'F_E | F_J'.(2416)

### 🙂 Expected behavior

No error

### Additional information about the issue

The following works with no error:
```
abstract class Rho {
abstract pidgins(brusquest: F_J | F_E): F_J | F_E;
abstract pidgins(brusquest: F_J | F_E): F_J | F_E;
}
class Bluffer extends Rho {
pidgins(brusquest: F_J | F_E): F_J | F_E
{
return brusquest;
}
}

```

Commencez par reproduire l’exemple du TypeScript Playground lié et comparez la méthode générique dans Rho avec l’implémentation dans Bluffer. Suivez le chemin de vérification des types pour la compatibilité des méthodes génériques ; le travail est terminé lorsque la reproduction ne signale aucune erreur sans casser le comportement d’assignabilité associé.

Rédigé par le modèle d'indexation à partir du texte de l'issue.