Mixins created from `obj.constructor` cannot have members

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### 🔎 Search Terms

mixin constructor property instance

### 🕗 Version & Regression Information

- This is the behavior in every version I tried, and I reviewed the FAQ for entries about mixins

### ⏯ Playground Link

https://www.typescriptlang.org/play/?ts=5.7.3#code/C4TwDgpgBAwg9gOwM7AE4FcDGw6oDwAqAfFALxQIQDuAFAHQMCGqA5kgFxSMIgDaAugEoyJAgG4AUBMwAbRkiRQAYnDhQA3hKhQA9DqgB1XAGsuqOOgQATKAAtgwMBz0sAlsFvoARnUxwAtjr+rpjmSHAAZsA6BOAQAMqhrmDRrgroEEg6AMwAHAAsAIxaUFYQsszQvABEfshoWDio1fyc8PUY2Lh4HmlEkgC+UhGW2K6IUACyrgAergiFhFAQM8AQ1ortKJ1NeCpwREQ0SOiQqBUKnATCmtp6UADyANIlqBDA6KgIUBeKK2sbKAnM6-DQlbQRVQRGg3IbaAaDYajYDjb7TOYIABMS3+6ysin2RzgXgAVlcbiV7jA5AooAByGgAQQQiBA-gsil+gjpUHmflQb2wMhAy1WeMUXnk0FBdIIdLolP09KZLJ47PQnJpSG5vMU8iQrhYCEYXhk0BwUA80sQ20Y82AUEilri9LlABooF50A7ZTy-OgZDYvNB5ihuCjGGsbFR3LYuKVXBEIhA3ggHScvKBII6Ij8bWg7Wn6ft5a93p9vqDcYDiSTfPmdrgwdoIVCYRo4VAERIhkA

### 💻 Code

```ts
type Constructor = new(...args: any[]) => T;

class Foo {
// Work around https://github.com/microsoft/TypeScript/issues/3841
declare ["constructor"]: Constructor;
}

function Mixin1>(superclass: T) {
// OK
return class extends superclass {
foof() {}
};
}

function Mixin2(obj: T) {
// Class '(Anonymous class)' incorrectly extends base class 'T'.
// '(Anonymous class)' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint 'Foo'.
return class extends obj.constructor {
foof() {}
};
}
```

### 🙁 Actual behavior

`Mixin1` compiles fine, but `Mixin2` has an error:

```
Class '(Anonymous class)' incorrectly extends base class 'T'.
'(Anonymous class)' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint 'Foo'.
```

Removing the `foof` member causes it to compile without error.

### 🙂 Expected behavior

Both should compile fine because they are doing the same thing.

### Additional information about the issue

_No response_

Comienza ejecutando la reproducción vinculada en TypeScript Playground y compara Mixin1 con Mixin2, centrándote en la expresión de herencia de clase que usa obj.constructor. El issue estará terminado cuando Mixin2 pueda conservar su miembro foof sin el error de herencia reportado, mientras Mixin1 siga compilando.

Escrito por el modelo de indexación a partir del texto del issue.