Support a built-in type for well-formed strings

🔍 Search Terms

"Unicode", "well-formed Unicode", "valid Unicode", "lone surrogates", ""UTF-16", "UTF-8", "isWellFormed()", "toWellFormed()"

✅ Viability Checklist

• This wouldn't be a breaking change in existing TypeScript/JavaScript code
• This wouldn't change the runtime behavior of existing JavaScript code
• This could be implemented without emitting different JS based on the types of the expressions
• This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, new syntax sugar for JS, etc.)
• This isn't a request to add a new utility type: https://github.com/microsoft/TypeScript/wiki/No-New-Utility-Types
• [?] This feature would agree with the rest of our Design Goals: https://github.com/Microsoft/TypeScript/wiki/TypeScript-Design-Goals

⭐ Suggestion

ES2024 now has String.isWellFormed() and String.toWellFormed(), which are supported in TypeScript's ES2024 type definitions.

But significant value from these functions is not realized in TypeScript because of the lack of a well-formed string type.

What I'd like to see is a "well-formed string" type (itself a super-type of String) for which isWellFormed() serves as a type guard and toWellFormed() (as well as functions like TextDecoder.decode()) return the well-formed string type.

Additionally, string literals could be determined to be of the well-formed string type at compile time.

This way TypeScript developers could get type safety for scenarios where strings need to be guaranteed to be well-formed.

📃 Motivating Example

I'm working on a TypeScript implementation of CEL which requires passing well-formed UTF-8 strings into an evaluation environment. If I want to bridge TypeScript's type safety to CEL's type safety, I'll need a well-formed string type in TypeScript.

💻 Use Cases

I can do something like this in my project:

interface WellFormedString extends String {
  __brand: "WellFormed";
}

interface String {
  isWellFormed(): this is WellFormedString;
  toWellFormed(): WellFormedString;
  toUpperCase(): this extends WellFormedString ? WellFormedString : string;
  toLowerCase(): this extends WellFormedString ? WellFormedString : string;
}

interface TextDecoder {
  decode(input?: AllowSharedBufferSource, options?: TextDecodeOptions): WellFormedString;
}

function useWellFormedString(a: WellFormedString) {
  // ...
}

// good -- no error
useWellFormedString("hello".toWellFormed());

// good -- no error
useWellFormedString("hello".toWellFormed().toUpperCase());

// good -- no error
const h = "hello";
if (h.isWellFormed()) {
  useWellFormedString(h); 
}

// good -- no error
// (the decoder coerces a lone "WTF-8" surrogate to "\ufffd\ufffd\ufffd")
useWellFormedString(new TextDecoder().decode(new Uint8Array([0xed, 0xba, 0xad])))

// good -- error
// (malformed string with lone UTF-16 surrogate)
useWellFormedString("\udead");

// bad -- error
useWellFormedString("hello");

// bad -- error
useWellFormedString("hello" as WellFormedString);

But there are some significant disadvantages here:

1. Well-formed string literals are not recognized as well-formed.
2. Uses a branding hack.
3. The compiler complains about casting (maybe this is fixable, but I don't know how).

Commencer par src/lib/es2024.string.d.ts et les déclarations existantes de String.isWellFormed() et String.toWellFormed(). Examiner ensuite la manière dont TypeScript gère les littéraux de chaîne, les type guards et TextDecoder.decode() ; le travail serait terminé lorsqu’une conception de type de chaîne bien formée aurait été arrêtée, avec le comportement de vérification de types et les tests correspondants.