Mixin constructor not working with `args:unknown[]`, only with `args:any[]`

🔎 Search Terms

site:github.com/microsoft/typescript mixin class "unknown" args any args

🕗 Version & Regression Information

• This changed most likely after unknown was introduces and the bespoke/unique mixin type checking logic wasn't updated.

⏯ Playground Link

https://www.typescriptlang.org/play/?#code/C4TwDgpgBAwg9gOwM7AE4FcDGw6qgXigQgHcoAKAOmoENUBzJALinQQGsE4SEBtAXQCUBAHxQ4AIwBWEbACg5AMzbYAloigAxOHAA8AFSgQAHsAgIAJkliIUGbLhHkAQjSQQW+4QG85Uf1CoEMDoqAhQmAA2btbacEam5lZQru5QvgGZEbZoWDioVLQMzKwcXDwCPn5ZNUjokAXUlHSMgtU1AL4KNf6KOgRQAIwATADM3T19cACywQAWcBbkPoHBoeHAc6pIlFNQXZldXUA

💻 Code

type Constructor = new (...args: unknown[]) => object

function Foo<T extends Constructor>(Base: T) {
    return class Foo extends Base { // <---------------- ERROR
        constructor(...args: unknown[]) {
            super(...args)
        }

        foo = 123

        fooMethod() { return this.foo }
    }
}

Change the unknown to any and the error goes away. You'd think they should behave the same: you don't care what the args are, you just need to pass them along.

Here's how to fix the error, changing unknowns to anys:

playground

Code:

type Constructor = new (...args: any[]) => object

function Foo<T extends Constructor>(Base: T) {
    return class Foo extends Base { // <---------------- ERROR
        constructor(...args: any[]) {
            super(...args)
        }

        foo = 123

        fooMethod() { return this.foo }
    }
}

🙁 Actual behavior

Type error on Foo.

🙂 Expected behavior

I expected it to allow "any unknown args" to be passed along.

Additional information about the issue

Plus, with an unknown type, the code in the mixin constructor can actually be more type safe, requiring type narrowing or type casting to use the args at all, whereas any allows anything to be done to the args which is not safe.

Maybe the mixin type checking algo could cast the base class constructor to new (...args: any[]) and simply allow anything to be passed in, to make unknown work. Then the mixin type checking algo could still enforce any[] as well as (more preferably) unknown[].

Also, maybe it would make sense to have an implicit Constructor type built into the mixin type checking algo so that mixins can just be really easy for plain JS users who are migrating to TypeScript.

I've met multiple people who are baffled by how difficult it is to write mixins in TypeScript when they come from plain JavaScript.

Beginne mit der verknüpften TypeScript Playground-Reproduktion und verfolge die im Bericht beschriebene spezielle oder einzigartige Mixin-Typprüfungslogik. Vergleiche die bereitgestellten Konstruktorbeispiele mit unknown[] und any[], und überprüfe anschließend, dass die Regressionstests das erwartete Mixin-Verhalten abdecken.