Literal tested as key of a certain type cannot be used as an index type

🔎 Search Terms

"literal", "extends", "keyof", "cannot be used to index type", "conditional"

🕗 Version & Regression Information

Versions: ^5.0 (regression)

⏯ Playground Link

https://www.typescriptlang.org/play?ts=5.3.3&ssl=7&ssc=54&pln=1&pc=1#code/C4TwDgpgBAKlC8UDeBYAUFKBrAXFAziALYBGA9gDYA06mZwAFhAE57mUQCGAdlVAPT8oPek2bYIIAhAhF8UZhACOAVwCWigCZQAZmXGNoJFQHMowMsLCROzdAF906QbHDQA5ACIsn91ADGPNz0UCTQKvgQ2pzyPFBq3JoQAB7mbgB0ABQATACsAMwAHACU6KCQUADCCFDuWH4pwBCJ8liSZDqwUAD8sADade4AulB43BAAbiwA3AJCPCBAA

💻 Code

type T = {
  k: symbol,
  other: boolean, // another key seems required for the bug to appear
}

// Type '"k"' cannot be used as an index type.(2538)
type C = 'k' extends keyof T ? T['k'] : never; // any

🙁 Actual behavior

An error is produced in the positive clause of the conditional type.
The resulting type is incorrect.

🙂 Expected behavior

No error.

Additional information about the issue

No response

Inizia eseguendo la riproduzione in TypeScript Playground collegata nell’issue con TypeScript 5.3.3, quindi confronta il comportamento tra le versioni ^5.0 segnalate. Traccia il controllo del tipo condizionale e dell’accesso indicizzato coinvolti nell’esempio; il lavoro è completato quando la clausola positiva non produce errori e il tipo risultante è corretto.