ES6 Class: `asserts this is Type` raises error when variable containing instance is type narrowed

Bug Report

🔎 Search Terms

• Error: "Assertions require every name in the call target to be declared with an explicit type annotation"
• Assertation function as class method
• Type narrowing class and then calling assertation method

🕗 Version & Regression Information

• This is the behavior in every version I tried, and I reviewed the FAQ for entries about this

⏯ Playground Link

Playground link with relevant code

💻 Code

class MyClass {
	public assertIsMyClass(): asserts this is MyClass {
		if (!(this instanceof MyClass)) {
			throw new Error('this was not of type MyClass');
		}
	}
}

const maybeMyClass: MyClass | undefined = new MyClass();

if (maybeMyClass) {
	// This fails with error:
	// Assertions require every name in the call target to be declared with an explicit type annotation.(2775)
	maybeMyClass.assertIsMyClass();

	// But if we simply assign to a new variable without the optionality, it's fine:

	// this line works because we have narrowed the type through the if statement above
	const definitelyMyClass: MyClass = maybeMyClass; 
	// This raises no error even though it's equivalent to the first attempt
	definitelyMyClass.assertIsMyClass();
}

🙁 Actual behavior

Calling the class method assertation function raises error: "Assertions require every name in the call target to be declared with an explicit type annotation.(2775)"

🙂 Expected behavior

It should pass validation and narrow to the type given in the assertation.
This is because it will have this behavior if you simply assign to a new variable with a new type annotation (but which is equivalent to the narrowed type at that point).

从提供的 Playground 链接开始，在代码示例中重现该诊断，将经过缩窄的变量与显式标注的变量进行比较。跟踪 TypeScript 编译器中的断言调用验证，并为这个类方法场景添加覆盖。完成的标准是缩窄后的调用通过验证，同时现有的断言检查仍然正确。