microsoft / microsoft/TypeScript

Support `satisfies` in type declaration

Abierto
#52,222 16 comentarios 47 reacciones 0 asignados Ver en GitHub

Nadie ha tomado este issue todavía.

Awaiting More Feedback Suggestion
Lenguaje dominante
Go
Estrellas
111k
Forks
14.4k
Merge medio
1 d 19 h
PR fusionados (30 d)
117

Descripción

Suggestion

satisfies should work in type declarations, similar to how it works currently.

i.e. similar to

const x = y satisfies Z;

we could have

type X = Y satisfies Z;

🔍 Search Terms

satisfies, type

✅ Viability Checklist

My suggestion meets these guidelines:

  • This wouldn't be a breaking change in existing TypeScript/JavaScript code
  • This wouldn't change the runtime behavior of existing JavaScript code
  • This could be implemented without emitting different JS based on the types of the expressions
  • This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, new syntax sugar for JS, etc.)
  • This feature would agree with the rest of TypeScript's Design Goals.

📃 Motivating Example

Say there is some library, 'to-upper', that deals with lower case letters, both Roman and Greek.

// external library 'to-upper@1.0.0'

export type LowercaseChar = 
  | 'a' | 'b' | 'c' | 'd' | 'e' | 'f' | 'g' | 'h' | 'i' | 'j' | 'k' | 'l' | 'm' | 'n' | 'o' | 'p' | 'q' | 'r' | 's' 
  | 't'  | 'u' | 'v' | 'w' | 'x' | 'y' | 'z' |  'α' | 'β' | 'γ' | 'δ' | 'ε' | 'ζ' | 'η' | 'θ' | 'ι' | 'κ' | 'λ' 
  | 'μ' | 'ν' | 'ξ' | 'ο' | 'π' | 'ρ' | 'σ' | 'τ' | 'υ' | 'φ' | 'χ' | 'ψ' | 'ω';
export type UppercaseChar = ...;
export const toUpper = (lower: LowercaseChar): UppercaseChar => ...

And I want to use this library, but I actually only need to deal with a type that is narrower than LowercaseChar. I only need to deal with vowels. So I make my type,

// my-types.ts

export type LowercaseVowel = 'a' | 'e' | 'i' | 'o' | 'u' | 'α' | 'ε' | 'η' | 'ι' | 'ο' | 'ω' | 'υ';

and then I use it with 'to-upper'

// my-app.ts

import { lowerToUpper } from 'char.js';
import type { LowercaseVowel } from './my-types';

const myLowercaseVowel: LowercaseVowel = 'ω';
toUpper(myLowercaseVowel);

All good.

However, now the maintainer of "to-upper" decides they don't want to deal with Greek characters anymore, so they make a breaking change. Being diligent and considerate of their users, they update the LowercaseChar type definition as such:

// external library 'to-upper@2.0.0'
export type LowercaseChar = 
  | 'a' | 'b' | 'c' | 'd' | 'e' | 'f' | 'g' | 'h' | 'i' | 'j' | 'k' | 'l' | 'm' | 'n' | 'o' | 'p' | 'q' | 'r' | 's'
  | 't' | 'u' | 'v' | 'w' | 'x' | 'y' | 'z';
...

And I update my dependencies to to-upper@2.0.0.
It's true that my code will break on type checking, but it will fail where I've called toLower(), because my LowercaseVowel (which includes lowercase Greek characters) no longer satisfies the parameter of toLower(), LowercaseChar, which doesn't.

What would be preferable is if I had defined LowecaseVowel explicitly with the constraint that it satisfies LowecaseChar, i.e.

import type { LowercaseChar } from 'char.js';

type LowercaseVowel = 'a' | 'e' | 'i' | 'o' | 'u' | 'α' | 'ε' | 'η' | 'ι' | 'ο' | 'ω' | 'υ' satisfies LowercaseChar;

(Using the syntax suggested.)
If this were supported, I can see in the type declaration whether or not my narrow type satisfies the broader type.

💻 Use Cases

Similar to the above example, this could be used to narrow usages of overly broad types like any in third-party libraries, e.g.

// third-party library

export type Payload = { data: any };
export function handlePayload(payload: Payload) {
  ...
}

// my satisfying library

import { type Payload, handlePayload } from 'third-party-library';

export type SpecialPayload = { data: { foo: string } } satisfies Payload;
export function handleSpecialPayload(specialPayload: SpecialPayload) {
   handlePayload(specialPayload);
   ...
}

// consumer of my library
import { type SpecialPayload, handleSpecialPayload } from 'satisfying-library';

const mySpecialPayload: SpecialPayload = { data: { foo: 'bar' } };
handleSpecialPayload(mySpecialPayload);

In this particular contrived example, the same thing could be done with using interfaces interface SpecialPayload extends Payload { data: { foo: string; } }, but I'm sure you could think of more complex examples where interfaces cannot be used.

Guía de contribución

Abrir la guía de contribución

Primeros pasos

  1. Lee el issue completo y luego la guía de contribución del proyecto.
  2. Comenta en el issue que vas a ocuparte — evita que dos personas hagan lo mismo.
  3. Haz un fork del repositorio y trabaja en una rama.
  4. Abre un pull request que haga referencia al número del issue.

Línea de trabajo

Comienza revisando el comportamiento existente de las expresiones satisfies y los ejemplos de declaraciones type propuestos en este issue. Compara los ejemplos motivadores y los casos de uso y, a continuación, determina la semántica del sistema de tipos y la validación necesarias para la funcionalidad. El trabajo terminado debe incluir un diseño aceptado y cobertura para los escenarios mostrados de narrowing y restricciones de bibliotecas.

Escrito por el modelo de indexación a partir del texto del issue.

Evaluación

Stack tecnológico
typescript
Área
compilers
Tipo de issue
Nueva funcionalidad
Dificultad
5/5
Tiempo estimado
Más de una semana
Estado de actividad
Tranquilo
Claridad
Bastante claro
Aptitud para principiantes
38/100

Recibe los nuevos issues en tu correo

Un resumen breve de issues de GitHub para principiantes.