microsoft / microsoft/TypeScript

Cannot bracket-index into an object after checking it's existence on that object.

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#44,117 4 commenti 0 reazioni 1 assegnatario Vedi su GitHub

@DanielRosenwasser ci sta già lavorando.

Dal 20/5/2021.

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Descrizione

Bug Report

Cannot bracket-index into an object after checking it's existence on that object.

The same failure was reported in #43651, but I couldn't find a separate discussion or a ticket for this.

🔎 Search Terms
  • implicitly has an 'any' type
  • bracket indexing
🕗 Version & Regression Information

Worked in 4.2.4. Starts to break since 4.3.0-beta

⏯ Playground Link

Playground link

💻 Code
interface A {}
function foo(a:A) {
    if ('abc' in a) {
        const z = a;
        // Element implicitly has an 'any' type because expression of type '"abc"' can't be used to index type 'A'.
        // Property 'abc' does not exist on type 'A'.
        return z['abc']; 
    }
}
🙁 Actual behavior

Compiler gives an error that you cannot index into type 'A', since 'abc' does not exist in type 'A'

🙂 Expected behavior

Compiler recognizes the existence check and does not give an error.

Observation

This seems to be caused by the improvement in the control flow analysis/type inference. Before the type of z in the below example was 'never' prior to TS4.3, but now the compiler recognizes z being type A

Question : I have one question though, is it by design that it's allowed to index into never types?

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