overload + generic + infer breaks conditional types

TypeScript Version: 3.9.2, 4.0.0-beta (playground), 3.9.6, 3.9.7 (locally tested)

Search Terms: overload generic conditional

Code

type Wrap <T> = T & { wrap: T }
interface Data { id: number }
interface Foo {
    <K extends keyof Data> (): Wrap<Pick<Data, K>>;
    <K extends keyof Data> (): Wrap<Pick<Data, K>>;
}

type A = Foo extends (...args: any[]) => infer R ? 1 : 0;
type B = Foo extends (...args: any[]) => any ? 1 : 0;
declare let a: A, b: B;

a = b // Type '1' is not assignable to type '0'.(2322)

Expected behavior: compiles without error

Actual behavior: Type '1' is not assignable to type '0'

Playground Link: Link

Related Issues:

使用列出的编译器版本，在链接的 TypeScript Playground 中复现最小示例，然后跟踪 overload、generic inference 和 conditional type 的求值过程。完成的标准是：示例能够编译且不再出现报告的 assignment error，同时保留 A 和 B 的预期结果。