Spreading tuple into generic/type arguments

Search Terms

• spreading generic parameters
• generic parameter spread
• tuple generic spread
• spreading generic argument
• spreading typeArgument
• spreading type argument

Suggestion

Allow spreading of a tuple type into type arguments.

The idea is that a tuple of n elements gets spread into generic arguments with r arguments. If n is larger than r, only the first r items are used. If n is smaller than r it is possible to add elements after the spread argument. E.g.

function foo<A, B, C, D>() {
}

type ThreeType = [Foo, Bar, Baz];

foo<...ThreeType, Delta>();

Use Cases

I find myself repeating complex generic types. Ideally I could shorten lengthy repetition into a single type.

Examples

dialog.open takes three generic arguments, these have to be repeated each call. This makes the call less legible and reduces DRYness.

const dialogRef = this.dialog.open<
    PrinterSelectDialogComponent,
    PrinterSelectDialogData,
    OfferProductPrinter>(
        PrinterSelectDialogComponent,
        {
            data: {
                printer,
            },
        },
    );

After this proposal

export type PrinterSelectDialog = [
    PrinterSelectDialogComponent,
    PrinterSelectDialogData,
    OfferProductPrinter,
];


const dialogRef = this.dialog.open<...PrinterSelectDialog>(PrinterSelectDialogComponent, {
    data: {
        service,
    },
});

Checklist

My suggestion meets these guidelines:

• This wouldn't be a breaking change in existing TypeScript/JavaScript code
• This wouldn't change the runtime behavior of existing JavaScript code
• This could be implemented without emitting different JS based on the types of the expressions
• This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, etc.)
• This feature would agree with the rest of TypeScript's Design Goals.

首先查看提案及其示例，了解预期的泛型参数展开行为。完成的标准是支持类型参数中的元组展开，包括元组较长时进行截断，以及元组较短时保留末尾元素，同时不改变生成的 JavaScript。