microsoft / microsoft/TypeScript
the type of super() should be instance, not void
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Description
TypeScript Version: 3.8.3
Search Terms:
Code
class Sub extends Super {
constructor () { return super(); }
}
Expected behavior: no error
Actual behavior: TS2322
Playground Link:
Related Issues:
Contributor guide
First steps
- Read the whole issue, then the project's contributing guide.
- Comment on the issue to say you are picking it up — it saves two people doing the same work.
- Fork the repository and make your change on a branch.
- Open a pull request that references the issue number.
Research direction
Start by reproducing the TypeScript 3.8.3 example where a derived constructor returns super() and produces TS2322. Trace the type assigned to super() and compare it with the expected instance type. Done means this example produces no error while preserving the existing constructor checks.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- typescript
- Domain
- compilers
- Issue type
- Bug
- Difficulty
- 4/5
- Estimated time
- 3-5 days
- Activity status
- Stale
- Clarity
- Clearly specified
- Newbie friendliness
- 35/100