microsoft / microsoft/TypeScript

React: enforce correct usage of refs

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Needs Proposal Suggestion
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Descrizione

Potentially a use case for #12936

if you have a problem and you think exact types are the right solution, please describe the original problem here

https://github.com/microsoft/TypeScript/issues/12936#issuecomment-284590083

Search Terms

react refs exact type

Suggestion

In React, it's fairly common to use refs. This involves creating an object of a specific type, and then passing that value as a prop to a component, which will mutate/reassign its current property.

Currently it seem there is no way to use refs in a type safe way. They can be accidentally passed to the wrong component, and there will be no type error.

https://stackoverflow.com/questions/56378639/typescript-react-enforce-correct-ref-props

import * as React from 'react';

class Modal extends React.Component<{}> {
    close = () => {};
}

declare const modal: Modal;

modal.close();

const modalRef = React.createRef<Modal>();

// Let's try giving this ref to the correct component…
// No error as expected :-)
<Modal ref={modalRef} />;

class SomeOtherComponent extends React.Component<{}> {}

// Let's try giving this ref to the wrong component…
// Expected type error but got none! :-(
<SomeOtherComponent ref={modalRef} />;

IIUC, this is because ref={modalRef} is equivalent to:

declare let ref: { current: {} };
declare let modalRef: { current: { close: () => void } };
ref = modalRef;

… which will correctly not error, because modalRef is a subtype of the target type ref.

However, when we're passing a ref to a component, we want to make sure the ref argument value (modalRef) is a supertype, or exact match, of the parameter type (ref).

This is because the component is responsible for mutating the ref's current property—if we pass in a ref of the wrong type, it will be mutated to something else. Later, when we try to use the ref's current value, the value will not match the type:

// Now when we try to use this ref, TypeScript tells us it's safe to do so.
// But it's not, because the ref has been incorrectly assigned to another component!
if (modalRef.current !== null) {
    modalRef.current.close(); // runtime error!
}

I am looking for a way to catch these mistakes at compile time, with TypeScript.

Note if the target component is a subtype of React.Component, we will get errors as desired:

class SomeOtherComponent extends React.Component<{}> {
    foo = () => {}
}

// Let's try giving this ref to the wrong component…
// We got an error :-)
<SomeOtherComponent ref={modalRef} />;

Checklist

My suggestion meets these guidelines:

  • This wouldn't be a breaking change in existing TypeScript/JavaScript code
  • This wouldn't change the runtime behavior of existing JavaScript code
  • This could be implemented without emitting different JS based on the types of the expressions
  • This isn't a runtime feature (e.g. library functionality, non-ECMAScript syntax with JavaScript output, etc.)
  • This feature would agree with the rest of TypeScript's Design Goals.

Guida per i contributori

Apri la guida per i contributori

Come iniziare

  1. Leggi tutta la issue e poi la guida ai contributi del progetto.
  2. Commenta sulla issue per dire che te ne occupi tu — evita che due persone facciano lo stesso lavoro.
  3. Fai un fork del repository e lavora su un branch.
  4. Apri una pull request che faccia riferimento al numero della issue.

Direzione di ricerca

Non sono identificati file di implementazione né test. Inizia leggendo l’issue TypeScript #12936 collegata e gli esempi di React ref qui, quindi definisci un errore in fase di compilazione quando si passa un ref al componente sbagliato, preservando il comportamento a runtime.

Scritto dal modello di indicizzazione a partire dal testo della issue.

Valutazione

Stack tecnologico
react, typescript
Ambito
compilers
Tipo di issue
Funzionalità
Difficoltà
5/5
Tempo stimato
Più di una settimana
Stato di attività
Ferma
Chiarezza
Abbastanza chiara
Idoneità per principianti
30/100

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