Generic derived value type

Hey guys.
I can not see if I'm doing anything wrong here. I am expecting to be able to get exact type from generic type ...
Is this just limitation of typescript or i am doing anything whrong here?

TypeScript Version: 3.1.3

Search Terms:
Generic derived value type

Code

export type filterTypeName = 'price' | 'price_range';
export type priceFilterValue = {
  from: number;
  to: number;
};
export type priceRangeFilterValue = {
  fromRange: number;
  toRange: number;
};

export type filterValueType<T extends filterTypeName> =  
    T extends 'price' ? priceFilterValue
    : T extends 'price_range' ? priceRangeFilterValue : never;


type productFilterParameters<T extends filterTypeName> = {
  filter: T;
    value: filterValueType<T>;
};

function addProductFilter<T extends filterTypeName>(params: productFilterParameters<T>) { 
    switch (params.filter) { 
        case 'price':
            const priceFrom = params.value.from; //Property 'from' does not exist on type 'filterValueType<T>'    
            break;
        default:
            break;            
    }
}

// parameter value is derivered based on filter type... not working id function definition
addProductFilter({ filter: 'price', value: { from: 1, to: 2 } });

//expected behavior something like this

type productFilterParametersCorrect = {
    filter: 'price';
    value: priceFilterValue;
} | {
    filter: 'price_range';
    value: priceRangeFilterValue;
}

function addProductFilterCorrect(params: productFilterParametersCorrect) { 
    switch (params.filter) { 
        case 'price':            
            const priceFrom = params.value.from; // correct
            break;
        case 'price_range':
            const priceRangeFrom = params.value.fromRange; // correct
        default:
            break;            
    }
}

Expected behavior:
Code

const value: priceFilterValue

Actual behavior:
Code

const value: filterValueType<T>

Playground Link:
Playground

Related Issues:

Inizia con il Playground collegato e con l’esempio generico addProductFilter usando TypeScript 3.1.3, quindi confronta il comportamento del parametro generico con l’unione definita esplicitamente. Il lavoro è completato quando lo switch su params.filter fornisce le proprietà dei valori corrispondenti senza l’errore segnalato; il payload non menziona file o test del repository.