Suggestion: Automatically infer argument types in overloaded function implementation

Search Terms

infer, arguments, function, overload

Suggestion

For basic container types (Point, Size, Rect, ...) I often write constructors and methods with overloaded signatures so they can be called with the container type itself or with the separate components of the container as arguments. Example:

class Point {
    constructor(point: Point);
    constructor(x: number, y: number);
    constructor(arg1: Point | number, arg2?: number) {
        if (arg1 instanceof Point) {
            this.x = arg1.getX();
            this.y = arg1.getY();
        } else {
            this.x = arg1;
            this.y = arg2!;
        }
    }
}

And I always wonder why I have to specify the argument types in the implementation again when I already defined the possible types in the overload signatures.

In this simple Point type it is still pretty easy but imagine a Rect type which can work with four number arguments, two Point arguments, a Point and Size argument or a Rect argument. Manually writing the combined signature for all these overloaded signatures is cumbersome. And I don't want to use any here because I want type checking in the function body.

An alternative way to write this example is this:

class Point {
    constructor(point: Point);
    constructor(x: number, y: number);
    constructor(...args: [ Point ] | [ number, number ]) {
        const [ arg1, arg2 ] = args;
        // arg1 is now Point | number
        // arg2 is now number | undefined (At least since TS 3.2 because of #27543)
        ...
    }
}

This shows how easy it should be for TypeScript to collect the possible function signatures into a union type so writing constructor(...args) would be enough.

Taking this a step further I even like to write this so I don't need to destructure the arguments myself:

class Point {
    constructor(point: Point);
    constructor(x: number, y: number);
    constructor(arg1, arg2) {
        // arg1 is now Point | number
        // arg2 is now number | undefined
        ...
    }
}

Taking this ANOTHER step further TypeScript could even narrow down the inferred function signatures by each type check done within the function body:

class Point {
    constructor(point: Point);
    constructor(x: number, y: number);
    constructor(arg1, arg2) {
        if (arg1 instanceof Point) {
            // arg2 can now only be `undefined` because the instanceof check removes 
            // the second call signature (where arg1 is a number) from the list of possible 
            // call signatures
            this.x = arg1.getX();
            this.y = arg1.getY();
        } else {
            // arg2 can now only be `number` because the failed instanceof check removes 
            // the first call signature from the list of possible signatures
            this.x = arg1;
            this.y = arg2;
        }
    }
}

I guess the type narrowing is harder to implement but at least the automatic type inference of each argument shouldn't be that hard. So it would be very nice if a future version of TypeScript could do this so using overloading gets a bit easier.

Checklist

My suggestion meets these guidelines:

• This wouldn't be a breaking change in existing TypeScript / JavaScript code
• This wouldn't change the runtime behavior of existing JavaScript code
• This could be implemented without emitting different JS based on the types of the expressions
• This isn't a runtime feature (e.g. new expression-level syntax)

L'issue non indica file né test. Inizia tracciando la gestione degli overload e l'inferenza dei tipi degli argomenti di TypeScript, quindi confronta gli esempi di Point con il comportamento attuale del compilatore; il lavoro è completo quando le implementazioni degli overload possono inferire tipi di parametro compatibili mantenendo il controllo dei tipi e il narrowing nel corpo.