graphql-python / graphql-python/aiohttp-graphql
python 3.5.3 SyntaxError: invalid syntax
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https://github.com/graphql-python/aiohttp-graphql/blob/a7aa6c6c1e9bda5842591b2a91ad800408a21b36/aiohttp_graphql/graphqlview.py#L39
Hi! I'm using python 3.5.3.
This line cause **SyntaxError: invalid syntax exception** because of trailing comma.
I think it should be removed for compatibility with older python versions.
Thank you!
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