Python: `FlaskApp` instances do not reliably track subclasses
- 主要语言
- CodeQL
- 星标
- 10.1k
- 派生
- 2.1k
- 平均合并
- 2 天 15 小时
- 30 天内合并 PR
- 141
描述
I was running a set of queries on the [CTFd](https://github.com/CTFd/CTFd) repository, and got suspiciously few results for endpoints. After some experimenting I found out that [they subclass `Flask`](https://github.com/CTFd/CTFd/blob/master/CTFd/__init__.py#L51C1-L91C1), which the current query for `FlaskApp::instance()` does not seem to track.
# Minimal example:
Query:
```plaintext
import python
import semmle.python.frameworks.Flask
import semmle.python.ApiGraphs
from API::Node node
where Flask::FlaskApp::instance() = node
select node
```
Python:
```py
from flask import Flask
class Sub(Flask):
def __init__(self, *args, **kwargs):
Flask.__init__(self, *args, **kwargs)
app = Sub(__name__)
@app.route("/")
def hello():
return "world"
```
CodeQL is not able to identify `Sub` as a Flask app, which means the route setup for `hello` cannot be detected as well.
Adding `.getASubclass*()` to [FlaskApp::instance()](https://github.com/github/codeql/blob/main/python/ql/lib/semmle/python/frameworks/Flask.qll#L76C1-L76C64) would probably fix this. If this can be overridden without changes to the library I am open to suggestions, my knowledge of the QL modules is not that great as of now.
贡献指南
调研方向
Start in python/ql/lib/semmle/python/frameworks/Flask.qll at FlaskApp::instance(), then reproduce the minimal query and Python subclass example from the issue. Confirm that a Flask subclass is recognized as an app and that the route for hello is detected; add or update the relevant library coverage test if one is found nearby.
由索引模型根据 Issue 内容生成。
评估
- 技术栈
- python
- 领域
- security
- Issue 类型
- 缺陷
- 难度
- 3/5
- 预计耗时
- 1-2 天
- 活跃度
- 冷清
- 描述清晰度
- 基本清楚
- 新手友好度
- 55/100