github / github/codeql

How can I use codeql cli without metadata?

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描述

This is a snippets from codeql's example:

```
/**
* @id java/examples/method-call
* @name Call to method
* @description Finds calls to com.example.Class.methodName
* @tags call
* method
*/

import java

from MethodAccess call, Method method
where
call.getMethod() = method and
method.hasName("methodName") and
method.getDeclaringType().hasQualifiedName("com.example", "Class")
select call, method
```

When I try to run it, codeql give me this error

```
Error was: Cannot process query metadata for a query without the '@kind' metadata property. To learn more, see https://codeql.github.com/docs/writing-codeql-queries/metadata-for-codeql-queries/ [NO_KIND_SPECIFIED]
```

I understand that this is because I didn't add a `@kind` in the metadata. So I added ` @kind problem` and received a new error:

```
Error was: Expected result pattern(s) are not present for problem query: Expected at least 2 columns. [INVALID_RESULT_PATTERNS]
```

My problem is: I don't care about the metadata at all. I just want to use it like a database query and I just want to get the raw result as a csv file.

Is there anyway that I can draft my own query without bothering the metadata?

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