github / github/codeql

How to filter the result of hasFlowPath API

Ouverte
#10,659 3 commentaires 0 réactions 0 personnes assignées Voir sur GitHub
question
Langage dominant
CodeQL
Étoiles
10.1k
Forks
2.1k
Merge moyen
2 j 15 h
PR mergées (30 j)
141

Description

I want to operate each node in the result of hasFlowPath(source, sink) data flow.

For example, I want to get every method call in the `A a to if(c)` data flow. The results I expect are getA, getB, getC. But the `hasFlowPath()` API only return the dataflow path which can not be

But the result of `hasFlowPath()` API contains only the nodes of the data flow, so there is no way to distinguish the method call node from it.

```
A a = getA();
B b = getB(a);
C c = getC(b);
if(c){
xx
}
```

Guide de contribution

Ouvrir le guide de contribution

Évaluation

Cette issue n'a pas encore été évaluée.

Recevez les nouvelles issues par e-mail

Un résumé court des issues GitHub adaptées aux débutants.