wsl terminal args issue when it use python interpreter on windows.

Nessuno ha ancora preso questa issue.

I am using wsl as vscode default terminal. but I want execute my python script using window python interpreter.
```python
{
...
"code-runner.executorMap": {
"python": "/mnt/c/Python27_64/python.exe -u",
},
"code-runner.runInTerminal": true,
...
}
```
above is my custom option to do what I want. but I got argument error.
```
root@local:~/home/test# /mnt/c/Python27_64/python.exe -u "/mnt/c/Users/user/home/test.py"
C:\Python27_64\python.exe: can't open file '/mnt/c/Users/user/home/test.py': [Errno 2] No such file or directory
```
windows python interpreter use windows path form for the script which passed first argument. so if I change command line by hand then it works.
```
root@local:~/home/test# /mnt/c/Python27_64/python.exe -u "c\\Users\\user\\home\\test.py"
```
It would be great if there is way to change wsl path to window path form. how can I do that? or where can I hook code runner's process? and I think it would be nice if code runner support contrary case.

Start by reproducing the command from the reported executorMap with runInTerminal enabled, using a WSL terminal and a Windows Python interpreter. Trace how Code Runner launches the script and handles its path; done means the Windows interpreter receives a usable Windows-form path, with the requested reverse case considered as well.

Scritto dal modello di indicizzazione a partire dal testo della issue.