dry-python / dry-python/returns

Motivation behind not being able to get IO's content, and IO-wrapped interfacing with unwrapped (normal) code

Aberta
#445 2 comentários 0 reações 0 responsáveis Ver no GitHub
Linguagem predominante
Python
Estrelas
4.4k
Forks
155
Merge médio
2h 27min
PRs com merge (30d)
22

Descrição

Hi! Question(s) on `IO`.

I am trying to write a little wrapper for some stateful operation (imagine I have to do IO from/to a file), and I found out that `IO` containers are designed to hide their content. It's impossible to get the value of, say, a successful read result (nothing like `IOSuccess.unwrap()`), unless one uses `unsafe_perform_io`.

What is the rationale behind this design? I am asking because I am not familiar with writing typed functional code, and I could not find a motivation in the documentation for why it shouldn't be possible to get the raw content of an `IO` container.

---

Second question related to interface between IO-wrapped code and normal "unsafe" code:

Let's say I am writing code A where want to mark and wrap all IO operations. Now, code A has to interface with standard python code B. What choices do I have to make them talk?

Do I have to unwrap all my operations with `unsafe_perform_io`, in case I want to do something simple like getting a string from my wrapped code? Do I have to rewrite code B by making it all safe and IO-wrapped, so that they can communicate with no "unsafe" bridge between them?

It seems that in such scenario I would end up with code pieces that are of "different colors" - using the usual async-vs-sync metaphore of incompatible red and blue code -, and I would be forced to make everything of the same color.

(Here "red code" = "python code written in railway style" and "blue code" = "standard procedural python code").

Guia de contribuição

Abrir o guia de contribuição

Avaliação

Esta issue ainda não foi avaliada.

Receba novas issues na sua caixa de entrada

Um resumo curto de issues do GitHub para quem está começando.