dry-python / dry-python/lambdas
How to get access to args/kwargs inside lambda?
Open
- Dominant language
- Python
- Stars
- 286
- Forks
- 6
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Description
Is it possible to express this kind of lambda?
`lambda a, b: a * b`
I intuitively tried this approach, but it doesn't work...
`_._1 * _._2`
Contributor guide
Research direction
No file, test, or entry point is named in the issue. Start by locating the implementation and tests for placeholder-based lambda expressions, then determine whether positional and keyword arguments can be represented; done means the requested lambda form or an explicitly documented limitation is covered by tests.
Written by the indexing model from the issue text.
Assessment
- Tech stack
- python
- Domain
- tooling
- Issue type
- Feature
- Difficulty
- 5/5
- Estimated time
- Over a week
- Activity status
- Stale
- Clarity
- Mostly clear
- Newbie friendliness
- 25/100