carloscn / carloscn/structstudy
leetcode2570: Merge Two 2D Arrays by Summing Values
@carloscn ya está trabajando en esto.
Desde el 13/11/2023.
- Lenguaje dominante
- C
- Estrellas
- 4
- Forks
- 1
- Métricas de merge de PR
- Sin PR fusionados en 30 d
Descripción
### Description
You are given two 2D integer arrays nums1 and nums2.
nums1[i] = [idi, vali] indicate that the number with the id idi has a value equal to vali.
nums2[i] = [idi, vali] indicate that the number with the id idi has a value equal to vali.
Each array contains unique ids and is sorted in ascending order by id.
Merge the two arrays into one array that is sorted in ascending order by id, respecting the following conditions:
Only ids that appear in at least one of the two arrays should be included in the resulting array.
Each id should be included only once and its value should be the sum of the values of this id in the two arrays. If the id does not exist in one of the two arrays then its value in that array is considered to be 0.
Return the resulting array. The returned array must be sorted in ascending order by id.
#### Example 1:
Input: nums1 = [[1,2],[2,3],[4,5]], nums2 = [[1,4],[3,2],[4,1]]
Output: [[1,6],[2,3],[3,2],[4,6]]
Explanation: The resulting array contains the following:
- id = 1, the value of this id is 2 + 4 = 6.
- id = 2, the value of this id is 3.
- id = 3, the value of this id is 2.
- id = 4, the value of this id is 5 + 1 = 6.
#### Example 2:
Input: nums1 = [[2,4],[3,6],[5,5]], nums2 = [[1,3],[4,3]]
Output: [[1,3],[2,4],[3,6],[4,3],[5,5]]
Explanation: There are no common ids, so we just include each id with its value in the resulting list.
Constraints:
1 <= nums1.length, nums2.length <= 200
nums1[i].length == nums2[j].length == 2
1 <= idi, vali <= 1000
Both arrays contain unique ids.
Both arrays are in strictly ascending order by id.
Guía de contribución
No hay ninguna guía de contribución indexada para este repositorio
Primeros pasos
- Lee el issue completo y luego la guía de contribución del proyecto.
- Comenta en el issue que vas a ocuparte — evita que dos personas hagan lo mismo.
- Haz un fork del repositorio y trabaja en una rama.
- Abre un pull request que haga referencia al número del issue.
Evaluación
Este issue todavía no se ha evaluado.