parquet.encryption.plaintext.footer parameter being true, code expects parquet.encryption.footer.key

Hi Team,

I want my footer in parquet file to be non encrypted. so I set the _parquet.encryption.plaintext.footer_ to be {_}true{_}, but when I tried to run my code, parquet-mr is expecting __ value __ for the __ property _parquet.encryption.footer.key  \*\*_  

Reproducer

Spark 3.3.0 

Download the [file\|[https://repo1.maven.org/maven2/org/apache/parquet/parquet-hadoop/1.12.0/parquet-hadoop-1.12.0-tests.jar] ] and place it in spark - jar directory 

using spark-shell
```java

sc.hadoopConfiguration.set("parquet.crypto.factory.class" ,"org.apache.parquet.crypto.keytools.PropertiesDrivenCryptoFactory") sc.hadoopConfiguration.set("parquet.encryption.kms.client.class" ,"org.apache.parquet.crypto.keytools.mocks.InMemoryKMS") sc.hadoopConfiguration.set("parquet.encryption.key.list","key1a: BAECAwQFBgcICQoLDA0ODw==, key2a: BAECAAECAAECAAECAAECAA==, keyz: BAECAAECAAECAAECAAECAA==") sc.hadoopConfiguration.set("parquet.encryption.key.material.store.internally","false")
val encryptedParquetPath = "/tmp/par_enc_footer_non_encrypted"
val partitionCol = 1
case class nestedItem(ic: Int = 0, sic : Double, pc: Int = 0)
case class SquareItem(int_column: Int, square_int_column : Double, partitionCol: Int, nestedCol :nestedItem)
val dataRange = (1 to 100).toList
val squares = sc.parallelize(dataRange.map(i => new SquareItem(i, scala.math.pow(i,2), partitionCol,nestedItem(i,i))))
squares.toDS().show() squares.toDS().write.partitionBy("partitionCol").mode("overwrite").option("parquet.encryption.column.keys", "key1a:square_int_column,nestedCol.ic;").option("parquet.encryption.plaintext.footer",true).parquet(encryptedParquetPath)
```
I get the below error, my expectation is if I set properties for my footer to be plain text, why do we need keys for footer.

 
```java

 
Caused by: org.apache.parquet.crypto.ParquetCryptoRuntimeException: Undefined footer key
  at org.apache.parquet.crypto.keytools.PropertiesDrivenCryptoFactory.getFileEncryptionProperties(PropertiesDrivenCryptoFactory.java:88)
  at org.apache.parquet.hadoop.ParquetOutputFormat.createEncryptionProperties(ParquetOutputFormat.java:554)
  at org.apache.parquet.hadoop.ParquetOutputFormat.getRecordWriter(ParquetOutputFormat.java:478)
  at org.apache.parquet.hadoop.ParquetOutputFormat.getRecordWriter(ParquetOutputFormat.java:420)
  at org.apache.parquet.hadoop.ParquetOutputFormat.getRecordWriter(ParquetOutputFormat.java:409)
  at org.apache.spark.sql.execution.datasources.parquet.ParquetOutputWriter.(ParquetOutputWriter.scala:36)
  at org.apache.spark.sql.execution.datasources.parquet.ParquetFileFormat$$anon$1.newInstance(ParquetFileFormat.scala:155)
  at org.apache.spark.sql.execution.datasources.BaseDynamicPartitionDataWriter.renewCurrentWriter(FileFormatDataWriter.scala:298)
  at org.apache.spark.sql.execution.datasources.DynamicPartitionDataSingleWriter.write(FileFormatDataWriter.scala:365)
  at org.apache.spark.sql.execution.datasources.FileFormatDataWriter.writeWithMetrics(FileFormatDataWriter.scala:85)
  at org.apache.spark.sql.execution.datasources.FileFormatDataWriter.writeWithIterator(FileFormatDataWriter.scala:92)
  at org.apache.spark.sql.execution.datasources.FileFormatWriter$.$anonfun$executeTask$1(FileFormatWriter.scala:331)
  at org.apache.spark.util.Utils$.tryWithSafeFinallyAndFailureCallbacks(Utils.scala:1538)
  at org.apache.spark.sql.execution.datasources.FileFormatWriter$.executeTask(FileFormatWriter.scala:338)
  ... 9 more
```
 

**Reporter**: [Vignesh Nageswaran](https://issues.apache.org/jira/secure/ViewProfile.jspa?name=Nageswaran)

_{**Note**: *This issue was originally created as [PARQUET-2194](https://issues.apache.org/jira/browse/PARQUET-2194). Please see the [migration documentation](https://issues.apache.org/jira/browse/PARQUET-2502) for further details.*}

Beginne mit dem Reproducer und dem Stacktrace bei PropertiesDrivenCryptoFactory.java:88 und untersuche anschließend ParquetOutputFormat.java im Bereich der Erstellung der Verschlüsselungseigenschaften. Überprüfe, ob parquet.encryption.plaintext.footer=true weiterhin parquet.encryption.footer.key erfordert, und definiere den Abschluss so, dass die gemeldete Konfiguration ohne den Fehler Undefined footer key abgeschlossen wird.

Vom Indexierungsmodell aus dem Issue-Text verfasst.