[Postgres]: `?` JSON operator cannot be parsed without a space after the field name

When using `PostgreSqlDialect`, the question mark cannot be parsed if it is not followed by a space, whereas postgres accepts the query. The following code panics when parsing `broken`:

```rust
fn main() {
let broken = r#"SELECT user?'adress' FROM my_table"#;
let working = r#"SELECT user? 'adress' FROM my_table"#;

let working_parsed =
sqlparser::parser::Parser::parse_sql(&sqlparser::dialect::PostgreSqlDialect {}, working)
.expect("Failed to parse SQL query");
println!("{:?}", working_parsed);

let broken_parsed =
sqlparser::parser::Parser::parse_sql(&sqlparser::dialect::PostgreSqlDialect {}, broken)
.expect("Failed to parse SQL query");
println!("{:?}", broken_parsed);
}
```

首先執行隨附的 Parser::parse_sql 範例並使用 PostgreSqlDialect，比較兩種查詢形式。追蹤解析器如何處理欄位名稱旁邊的 ?，然後為兩種空格形式新增覆蓋，並確認 PostgreSQL JSON 運算子解析時不會 panic。

由索引模型根據 Issue 內容生成。