why string "hello" is "\x45hello" not "\x85hello"?

The length of "hello" is 5, it's less then 63, so it matches this format
```
10|xxxxxx
```

The first 2bit is `10`, and the rest 6bit representing the length of the ``, in this case, is 5(the length of "hello")，5 convert to binary code is `101`, we use `000` the make it reach 6bit, so it should be `000101`, `10` concat `000101` is `10000101`, convert it to hex is `0x85` not `0x45`, so am I wrong? or you make a mistake?